我正在尝试使用 R 中的 deSolve 对管道延迟进行建模。我有一个具有恒定输入 (work_arrival) 的库存 (worktodo),我想要一个管道延迟执行 (work_rate),其中库存以相同的到达率下降3 步延迟。目前,我能够初始化管道延迟,但它似乎在延迟后重置(开启 3 步,关闭 3 步,...)。它应该保持与 work_arrival 匹配。有任何想法吗?
####System Dyanmics Model - Pipeline Delay
library(deSolve)
library(tidyverse)
#model setup
finaltime = 50
initialtime = 0
timestep = 1
#create a time vector
simtime <- seq(initialtime, finaltime, by= timestep)
#add auxs
auxs <- c(
work_arrival = 50
)
#add stocks
stocks <- c(
worktodo= 600 )
# This is the model function
model <- function(time, stocks, auxs){
with(as.list(c(stocks, auxs)),{
#add aux calculations
tlag <- 3
if(time < tlag){
work_rate = 0
}
else{
ylag <- lagderiv(time - tlag)
work_rate <- ylag
}
#if(time == 3) print(structure(ylag))
#add stock calculations
worktodo = work_arrival - work_rate
#return data
return(list(c(
worktodo),
work_rate = work_rate,
work_arrival = work_arrival))
})
}
data <- data.frame(dede(y= stocks, times = simtime, func = model, parms = auxs, method = "lsodar"))
df <- data %>%
pivot_longer(-time, names_to = 'variable')
ggplot(df, aes(time, value, color = variable))+
geom_line(size =1.25)+
theme_minimal()