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我的数据很脏，现在我正在尝试纠正它们。

数据是这样的：

mysql> select attrs from goods  limit 10;
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| attrs                                                                                                                                                                                                                                                                    |
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L1", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1532572800000, "courseStartTime": 1531706400000}  |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L1", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1533717600000, "courseStartTime": 1532851200000}  |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L1", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1534851600000, "courseStartTime": 1533985200000}  |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L2", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1532594400000, "courseStartTime": 1531728000000}  |
| {"logo": "1", "cover": "", "level": 0, "tag_147": 8, "tag_145": 2 "summary": "L2", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1533728400000, "courseStartTime": 1532862000000}  |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L2", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1534819200000, "courseStartTime": 1533952800000}  |
| {"logo": "1", "cover": "", "level": 0, "tag_127": 8, "summary": "NGL", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1532605200000, "courseStartTime": 1531738800000} |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "NGL", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1533696000000, "courseStartTime": 1532829600000} |
|
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+

如果存在任何这些对，我想删除(key, value)列中的一些对。attrs例如tag_147，并且tag_124是脏的，那么任何命中对都会被删除。

{"tag_147": 1, "tag_124": 2}  ===>  {}
{"tag_147": 1 "tag_100":2}  ==>  {"tag_100": 2}

我怎样才能实现它？谢谢。

我尝试过的是 1. findattrs包含键tag_147和tag_124. 2. 然后更新 attrs。我原来的 Sql 是这样的：

update goods
set json_remove(*XXX*) 
where (select json_keys(attrs) from goods ) contains  (*tag_147*, *tag_127*)

在这里，我被构造contains 语句阻止了......

4

1 回答 1

1

如果您只想从同时attrs包含这两个标签的值中删除这两个标签，您可以JSON_REMOVE对 找到的任何attrs值JSON_CONTAINS_PATH使用 ，使用 的all模式JSON_CONTAINS_PATH仅查找包含这两个标签的值：

UPDATE goods
SET attrs = JSON_REMOVE(attrs, '$.tag_147', '$.tag_124')
WHERE JSON_CONTAINS_PATH(attrs, 'all', '$.tag_147', '$.tag_124')

如果要完全删除attrs值包含两个标签的行，可以在查询中使用相同的JSON_CONTAINS_PATH条件：DELETE

DELETE
FROM goods
WHERE JSON_CONTAINS_PATH(attrs, 'all', '$.tag_147', '$.tag_124')

dbfiddle 上的演示

如果要从attrs包含其中任何一个的值中删除这些标签，可以删除ie中的WHERE子句UPDATE

UPDATE goods
SET attrs = JSON_REMOVE(attrs, '$.tag_147', '$.tag_145')

要删除attrs包含任何标签的值的行，请将all参数更改JSON_CONTAINS_PATH为one：

DELETE
FROM goods
WHERE JSON_CONTAINS_PATH(attrs, 'one', '$.tag_147', '$.tag_145')

dbfiddle 上的演示

于 2020-03-05T05:43:16.417 回答