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我有一个名为 的变raw_json体表，其中包含多个 json 文件，这些文件对于 ID 是唯一的，但在每个 json 中包含相似的数据点。它们位于 jsontext 列中。这是上下文的SS。我正在尝试将表格的每一行展平raw_json为普通的表格视图。两个数组索引需要对齐以分配正确的值。

表名是 raw_json

这是表中的两行raw_json以及 json 的结构。

{
 "ID": "PO-103",
 "content": {
   "EEList": [
     {
       "EEListID": "PO-103-1",
       "EEProductID": "XXX1976",

     },
     {
       "EEListID": "PO-103-2",
       "EEProductID": "XXX1977",
     },
     {
       "EEListID": "PO-103-3",
       "EEProductID": "XXX1978",
     }
   ],
   "EENotesList": [
     {
       "FirstName": "John",
       "LastName": "Smith",
       "pxObjClass": "XX-XXSales-Work-XX"
     },
     {
       "FirstName": "Bob",
       "LastName": "Joe",
       "pxObjClass": "XX-XXSales-Work-XX"
     },
     {
       "FirstName": "Mike",
       "LastName": "Smith",
       "pxObjClass": "XX-XXSales-Work-XX"
     }
   ],
 }
}

{
  "ID": "PO-104",
  "content": {
    "EEList": [
      {
        "EEListID": "PO-104-1",
        "EEProductID": "XXX1979",

      },
      {
        "EEListID": "PO-104-2",
        "EEProductID": "XXX1980",
      },
      {
        "EEListID": "PO-104-3",
        "EEProductID": "XXX1981",
      }
    ],
    "EENotesList": [
      {
        "FirstName": "Sarah",
        "LastName": "Butler",
        "pxObjClass": "XX-XXSales-Work-XX"
      },
      {
        "FirstName": "Jessica",
        "LastName": "Adams",
        "pxObjClass": "XX-XXSales-Work-XX"
      }
    ],
  }
}

变成这样的表（我需要这个）

+--------+----------+-------------+-----------+----------+-------------------+
|   ID   | EEListID | EEProductID | FirstName | LastName |    pxObjClass     |
+--------+----------+-------------+-----------+----------+-------------------+
| PO-103 | PO-103-1 | XXX1976     | John      | Smith    | X-XXSales-Work-XX |
| PO-103 | PO-103-2 | XXX1977     | Bob       | Joe      | X-XXSales-Work-XX |
| PO-103 | PO-103-3 | XXX1978     | Mike      | Smith    | X-XXSales-Work-XX |
| PO-104 | PO-104-1 | XXX1979     | Sarah     | Butler   | X-XXSales-Work-XX |
| PO-104 | PO-104-2 | XXX1980     | Jessica   | Adams    | X-XXSales-Work-XX |
+--------+----------+-------------+-----------+----------+-------------------+

我已经能够将 EENoteList 数组展平为一个表并将正确的 ID 分配给该表。到目前为止，这是我的代码：在不展开表格的情况下添加 EEList 值是我出错的地方。

select
    jsontext:ID::varchar as ID,
    en.value:FirstName::varchar as FirstName,
    en.value:LastName::varchar as LastName,
    en.value:pxObjClass::varchar as pxObjClass
   -- concat(ID, EEProductID, FirstName, LastName)

    from raw_json,
    lateral flatten (input => jsontext:content:EENotesList, outer => false) en;

产生这张桌子（我有这个）

+--------+-----------+----------+-------------------+
|   ID   | FirstName | LastName |    pxObjClass     |
+--------+-----------+----------+-------------------+
| PO-103 | John      | Smith    | X-XXSales-Work-XX |
| PO-103 | Bob       | Joe      | X-XXSales-Work-XX |
| PO-103 | Mike      | Smith    | X-XXSales-Work-XX |
| PO-104 | Sarah     | Butler   | X-XXSales-Work-XX |
| PO-104 | Jessica   | Adams    | X-XXSales-Work-XX |
| PO-104 | Terrence  | Williams | X-XXSales-Work-XX |
+--------+-----------+----------+-------------------+
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1 回答 1

1

所以大多数情况下，这个答案是将数据放入 CTE 的序言，但是“iff”两个数组的顺序是同步的，你可以使用 flatten 的索引来访问另一种类型的原始数组：

WITH raw_json AS (
select PARSE_json(column1) AS jsontext FROM VALUES 
 ('{
 "ID": "PO-103",
 "content": {
   "EEList": [
     {
       "EEListID": "PO-103-1",
       "EEProductID": "XXX1976",

     },
     {
       "EEListID": "PO-103-2",
       "EEProductID": "XXX1977",
     },
     {
       "EEListID": "PO-103-3",
       "EEProductID": "XXX1978",
     }
   ],
   "EENotesList": [
     {
       "FirstName": "John",
       "LastName": "Smith",
       "pxObjClass": "XX-XXSales-Work-XX"
     },
     {
       "FirstName": "Bob",
       "LastName": "Joe",
       "pxObjClass": "XX-XXSales-Work-XX"
     },
     {
       "FirstName": "Mike",
       "LastName": "Smith",
       "pxObjClass": "XX-XXSales-Work-XX"
     }
   ],
 }
}'), ('{
  "ID": "PO-104",
  "content": {
    "EEList": [
      {
        "EEListID": "PO-104-1",
        "EEProductID": "XXX1979",

      },
      {
        "EEListID": "PO-104-2",
        "EEProductID": "XXX1980",
      },
      {
        "EEListID": "PO-104-3",
        "EEProductID": "XXX1981",
      }
    ],
    "EENotesList": [
      {
        "FirstName": "Sarah",
        "LastName": "Butler",
        "pxObjClass": "XX-XXSales-Work-XX"
      },
      {
        "FirstName": "Jessica",
        "LastName": "Adams",
        "pxObjClass": "XX-XXSales-Work-XX"
      }
    ],
  }
}') 
)
select
    jsontext:ID::varchar as ID,
    en.value:FirstName::varchar as FirstName,
    en.value:LastName::varchar as LastName,
    en.value:pxObjClass::varchar as pxObjClass,
    jsontext:content.EEList[en.index].EEListID::text as EEListID,
    jsontext:content.EEList[en.index].EEProductID::text as EEProductID
    from raw_json,
    lateral flatten (input => jsontext:content:EENotesList, outer => false) en;

这导致：

ID  FIRSTNAME   LASTNAME    PXOBJCLASS  EELISTID    EEPRODUCTID
PO-103  John    Smith   XX-XXSales-Work-XX  PO-103-1    XXX1976
PO-103  Bob     Joe     XX-XXSales-Work-XX  PO-103-2    XXX1977
PO-103  Mike    Smith   XX-XXSales-Work-XX  PO-103-3    XXX1978
PO-104  Sarah   Butler  XX-XXSales-Work-XX  PO-104-1    XXX1979
PO-104  Jessica Adams   XX-XXSales-Work-XX  PO-104-2    XXX1980
于 2020-03-05T03:37:54.613 回答