6

当 ListView 有超过 15000 个包含 9 个子项的列表时，从查询中填充 ListView 的最快方法是什么。加载大约需要 6 分钟。

这是我为填充 ListView 控件而编写的内容。

Set rs = db.OpenRecordset(strSQL, dbOpenForwardOnly, dbReadOnly)

With Me.listViewData
    .View = lvwReport
    .GridLines = True
    .FullRowSelect = True
    .ListItems.Clear
    .ColumnHeaders.Clear
End With
'Set up column headers
With Me.listViewData.ColumnHeaders
    .Add , , "Client", 1440, lvwColumnLeft
    .Add , , "Contact", 2160, lvwColumnLeft
    .Add , , "Quote #", 720, lvwColumnCenter
    .Add , , "Date", 1140, lvwColumnLeft
    .Add , , "GrandTotal", 1440, lvwColumnRight
    .Add , , "Weighted Value", 1440, lvwColumnRight
    .Add , , "Chance %", 500, lvwColumnRight
    .Add , , "Sales Cycle", 1140, lvwColumnRight
    .Add , , "Won Orders", 1000, lvwColumnRight
    .Add , , "SalesRep", 1000, lvwColumnRight
End With

While Not rs.EOF
    Set lstItem = Me.listViewData.ListItems.Add()
    lstItem.Text = Nz(rs!Name, "")
    lstItem.SubItems(1) = Nz(rs!Company, "")
    lstItem.SubItems(2) = Nz(rs!QuoteNumber, "")
    lstItem.SubItems(3) = Nz(rs!OrderDate, "")
    lstItem.SubItems(4) = Nz(Format(rs!GrandTotal, "Currency"), "0.00")
    lstItem.SubItems(5) = Nz(Format(rs!GrandTotal * rs!Customfield1 / 100, "Currency"), "")
    lstItem.SubItems(6) = Nz(rs!Customfield1, "")
    lstItem.SubItems(7) = Nz(rs!Date1, "none")
    lstItem.SubItems(8) = Nz(rs!Detail, "")
    lstItem.SubItems(9) = Nz(rs!CustomT1, Nz(rs!UserID, ""))

    For I = 1 To Me.listViewData.ColumnHeaders.Count - 1
        Set sb = lstItem.ListSubItems(I)
        If rs!Customfield1 = 100 Or Not IsNull(rs!List) Then
            sb.ForeColor = vbBlue
            lstItem.ForeColor = vbBlue
        ElseIf rs!Cancelled = -1 Then
            sb.ForeColor = vbRed
            lstItem.ForeColor = vbRed
        Else
            sb.ForeColor = vbBlack
            lstItem.ForeColor = vbBlack
        End If
        DoEvents
    Next
    rs.MoveNext
Wend
4

3 回答 3

2

首先你应该做的是摆脱“doevents”，这是一个真正的性能杀手。

您是否必须动态加载列表视图？为什么不直接将其绑定到数据源？

于 2009-03-03T00:41:26.683 回答
1

我能想到几件事：

While...Wend 是一种较慢的循环机制；使用 For...Next。For...Next 更快——即使您必须运行另一个命令来获取 RecordCount。这就是我使用的：

With rs
  If .RecordCount > 0 Then
    '-- MoveLast...MoveFirst will update the .RecordCount; depending on the type of DAO Recordset, RecordCount might only return "1" when there are more than that.
    .MoveLast
    .MoveFirst

    For lngCounter = 1 To .RecordCount
      '-- Code to add ListItems here

      .MoveNext
    Next lngCounter
  End If
  .Close
End With

使用 With...End With 添加您的子项：

With Me.listViewData.ListItems.Add
  .Text = Nz(rs!Name, "")
  .SubItems(1) = Nz(rs!Company, "")
  .SubItems(2) = Nz(rs!QuoteNumber, "")
  .SubItems(3) = Nz(rs!OrderDate, "")
  .SubItems(4) = Nz(Format(rs!GrandTotal, "Currency"), "0.00")
  .SubItems(5) = Nz(Format(rs!GrandTotal * rs!Customfield1 / 100, "Currency"), "")
  .SubItems(6) = Nz(rs!Customfield1, "")
  .SubItems(7) = Nz(rs!Date1, "none")
  .SubItems(8) = Nz(rs!Detail, "")
  .SubItems(9) = Nz(rs!CustomT1, Nz(rs!UserID, ""))
End With

将填充器代码包装在：

DoCmd.Echo False

'-- Populate code

DoCmd.Echo True

希望有帮助！

于 2009-03-09T17:50:17.067 回答
0

检查 Listview 控件的方法，例如 beginupdate / endupdate 或将 refresh 设置为 false（如果可能）。这意味着在添加每个项目后，UI 不会尝试刷新屏幕，从而使添加速度更快。

Listview 控件旨在获取大量项目，因此应该可以通过一些挖掘来实现。

于 2009-03-05T09:23:57.817 回答