python - 如何点击img元素？

Question

我正在尝试访问 selenium 中的以下类，但它显示 element not found 错误。

html

<button class="gpquestion-plusicon">
  <img src="./assets/images/viewdetails.png">
</button>

代码

driver.find_elements_by_css_selector("//img[@src='./assets/images/viewdetails.png']").click()

或者

driver.find_element_by_css_selector("//img[@src='./assets/images/viewdetails.png']").click()
driver.find_elements_by_xpath("//img[@src='./assets/images/viewdetails.png']").click()

例外

raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.InvalidSelectorException: Message: invalid selector: 
An invalid or illegal selector was specified

不幸的是，它们都不起作用。xpath 显示未找到元素错误。

有什么建议么？

Answer 1

您正在尝试使用xpathas css_selector。尝试

driver.find_element_by_css_selector("[src='./assets/images/viewdetails.png']").click()

或者

driver.find_element_by_xpath("//img[@src='./assets/images/viewdetails.png']").click()

您还可以使用显式等待

from selenium.webdriver.support import expected_conditions as ec
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By

wait = WebDriverWait(driver, 10)
wait.until(ec.element_to_be_clickable((By.CSS_SELECTOR, "[src='./assets/images/viewdetails.png']"))).click()
# or
wait.until(ec.element_to_be_clickable((By.XPATH, "//img[@src='./assets/images/viewdetails.png']"))).click()