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我在 .NET Core 3.1 项目中使用 Swashbuckle 和 Swagger UI,并将我的 XML 注释导入 Swagger。我在控制器上有一个 POST 请求,我想在 Swagger 中注册多个响应状态(201、401、403、404)。问题是我还看到一个200 Successswagger.json响应与我在文件和 Swagger UI 界面中明确指定的状态代码响应一起列出。

正如在多个不同的地方所建议的那样,我正在使用该[SwaggerResponseRemoveDefaults]属性来尝试防止这种情况发生,但是我尝试的所有操作仍然会导致列出默认的 200 响应。

我试过了:

  • 将属性添加到方法中,
  • 将属性添加到控制器,
  • 将属性添加到抽象基本控制器,

以及以上的所有组合。我还结合以下方法尝试了这些:

  • <response code="XXX"></response>使用 XML注释标签指定所需的响应类型,以及
  • [SwaggerResponse(XXX)]使用端点指定所需的响应类型。

从我的 Swagger UIswagger.json.

TrackerController.cs

/// <summary>...</summary>
/// <response code="401">User is not authenticated.</response>
/// <response code="404">Tracker not found.</response>
[Authorize]
[ApiController]
[Route("[controller]")]
[SwaggerResponseRemoveDefaults]
public partial class TrackersController : AbstractController
{
    ...

    /// <summary>...</summary>
    /// <param name="tracker">The details of the tracker to be created.</param>
    /// <response code="201">The tracker was successfully created.</response>
    /// <response code="403">User is not authorized to modify this resource.</response>
    [HttpPost]
    [SwaggerResponseRemoveDefaults]
    [ResponseType(typeof(TrackerDto))]
    [SwaggerResponse(201, Description = "The tracker was successfully created.")]
    public async Task<IActionResult> CreateTracker([FromBody] TrackerDto tracker)
    {
        ...
    }

    ...

}

招摇.json

{
  "openapi": "3.0.1",
  "info": {
    "title": "My API",
    "version": "v1"
  },
  "paths": {
    "/Trackers": {
      "post": {
        "tags": [
          "Trackers"
        ],
        "summary": "Create a new tracker.",
        "requestBody": {
          "description": "The details of the tracker to be created.",
          "content": {
            "application/json-patch+json": {
              "schema": {
                "$ref": "#/components/schemas/TrackerDto"
              }
            },
            "application/json": {
              "schema": {
                "$ref": "#/components/schemas/TrackerDto"
              }
            },
            "text/json": {
              "schema": {
                "$ref": "#/components/schemas/TrackerDto"
              }
            },
            "application/*+json": {
              "schema": {
                "$ref": "#/components/schemas/TrackerDto"
              }
            }
          }
        },
        "responses": {
          "200": {
            "description": "Success"
          },
          "201": {
            "description": "The tracker was successfully created."
          },
          "401": {
            "description": "User is not authenticated."
          },
          "403": {
            "description": "User is not authorized to modify this resource."
          },
          "404": {
            "description": "Tracker not found."
          }
        }
      }
    }
  }
}

招摇用户界面截图

4

1 回答 1

0

现在,您告诉 Swagger 您正在生成TrackerDto默认类型为 200 的a ,此外还有另一个响应为 201。您需要制作一个匹配对。

删除ResponseType属性并将类型放在它所属的位置:

[SwaggerResponse(201, Description = "The tracker was successfully created.", typeof(TrackerDto))]

你也可以试试:

[ProducesResponseType(typeof(TrackerDto), 201)]

重要的是将类型和状态码放在同一个属性中,这样 Swagger 就知道它们属于同一类。

于 2020-02-24T14:19:42.100 回答