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我有以下 plsql 块

declare 
    TYPE t_mds_ids IS TABLE OF mds.id%TYPE;
    l_mds_ids t_mds_ids;
    l_mds_parents t_mds_parents;
begin
    SELECT id BULK COLLECT INTO l_mds_ids FROM mds;
    FORALL indx IN l_mds_ids.FIRST .. l_mds_ids.LAST
        select l_mds_ids(indx), ch.id_employee_parent
        into l_mds_parents
        FROM hierarchy_all ch
        CONNECT BY ch.id_employee = prior ch.id_employee_parent
        START WITH ch.id_employee = l_mds_ids(indx);
    EXECUTE IMMEDIATE 'truncate table mds_hierarchy_all';
    insert into mds_hierarchy_all
    select * from l_mds_parents;
end;

t_mds_parents 声明为

create or replace type r_mds_parents as object (
  id_mds number(5,0),
  id_employee number(5,0)
);
/

create or replace type t_mds_parents as table of r_mds_parents;
/

我得到一个异常 ORA-00947：没有足够的值

我真的需要在 FORALL 循环的每次迭代中将多行的结果集放入 TABLE TYPE 的变量中。我不能在 l_mds_parents 中使用 BULK COLLECT，因为它在 FORALL 内部受到限制。是否只有使用临时表而不是表变量的解决方案？

4

1 回答 1

0

我不认为你可以用forall. 您可以使用嵌套循环：

declare 
    TYPE t_mds_ids IS TABLE OF mds.id%TYPE;
    l_mds_ids t_mds_ids;
    l_mds_parents t_mds_parents;
begin
    SELECT id BULK COLLECT INTO l_mds_ids FROM mds;
    l_mds_parents := NEW t_mds_parents();
    FOR indx IN l_mds_ids.FIRST .. l_mds_ids.LAST LOOP
        FOR rec IN (
            select l_mds_ids(indx) as id_employee, ch.id_employee_parent
            FROM hierarchy_all ch
            CONNECT BY ch.id_employee = prior ch.id_employee_parent
            START WITH ch.id_employee = l_mds_ids(indx)
            ) LOOP
                l_mds_parents.extend();
                l_mds_parents(l_mds_parents.COUNT)
                    := NEW r_mds_parents (rec.id_employee, rec.id_employee_parent);
        END LOOP;
    END LOOP;
    EXECUTE IMMEDIATE 'truncate table mds_hierarchy_all';
    insert into mds_hierarchy_all
    select * from table(l_mds_parents);
end;
/

但是你根本不需要使用 PL/SQL；使用单个分层查询，或者在这里可能更简单，递归子查询分解：

insert into mds_hierarchy_all /* (id_mds, id_employee) -- better to list columns */
with rcte (id_mds, id_employee) as (
  select m.id, ha.id_employee_parent
  from mds m
  join hierarchy_all ha on ha.id_employee = m.id
  union all
  select r.id_mds, ha.id_employee_parent
  from rcte r
  join hierarchy_all ha on ha.id_employee = r.id_employee
)
select * from rcte;

db<> 摆弄一些虚构的数据。

于 2020-02-21T11:47:39.067 回答