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我一直在寻找与此类似的问题，但没有成功。

我的目标：我需要获取创建某个实体的用户名，该用户名存储在通过 Spring 的 @AuditTable 引用的所述实体的审计表中。

有点（希望）解释：在这种特殊情况下，我将添加到使用 org.springframework.data.jpa.repository.JpaSpecificationExecutor 类以及 Predicate 类（javax.persistence.criteria.Predicate）构建的先前存在的查询中. 连接往往使用类的名称（例如 Join），然后 Spring 从中获取表名。我的问题是，有没有办法让 Spring 查看审计表名，而不是实体的表名？

一个例子是：

@Entity @Table(name = "persons")
@Audited @AuditTable(name = "audit_persons")
public class Person {
        private String id;
        private String name;
        private Job job;
        /*getters and setters*/
}

@Entity @Table(name = "jobs")
@Audited @AuditTable(name = "audit_jobs")
public class Job {
        private String id;
        private String name;
        /*getters and setters*/
}

public final class PersonSpecification {
    private PersonSpecification(){}

    public static Specification<Person> findBy(final String attributeName, final Object filterValue) {
        return new Specification<Person>() {
            @Override
            public Predicate toPredicate(Root<Person> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
                return cb.equal(root.get(attributeName), filterValue);
            }
        };
    }

    public static Specification<Person> findByJob(final Job job) {
        return new Specification<Person>() {

            @Override
            public Predicate toPredicate(Root<Person> root, CriteriaQuery<?> query, CriteriaBuilder cb) {

                Join<Person, Job> joinJob = root.join("job", JoinType.LEFT);
                return cb.equal(joinJob.<Job>get("job"), job);
            }
        };
    }

/*
    public static Specification<Person> findByUsername(final String username) {
        return new Specification<Person>() {
            @Override
            public Predicate toPredicate(Root<Person> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
                Join<Person, audit person?> join? = root.join(?, JoinType.LEFT);
                return I don't know how to access;
            }
        };
    }
*/
}

import static ().PersonSpecification.findBy;
import static ().PersonSpecification.findByJob;
@Service(value="personService")
public class PersonService {

    @Autowired
    private PersonDao personDao;

    public List<Person> find(String id, String name, Job job /*, String username*/){

        Specifications<Person> specifications = null;

        if (!StringUtils.isBlank(id) && StringUtils.isNumeric(id)) {
            specifications = loadFilter(specifications, findBy("id", id));
        }else{
            if (!StringUtils.isBlank(name)) {
                specifications = loadFilter(specifications, findBy("name", name));
            }
            if (job != null) {
                specifications = loadFilter(specifications, findByJob("job", job));
            }
            /*
            if (!StringUtils.isBlank(username)) {
                specifications = I don't know what to do here;
            }
            */
        }
        return personDao.findAll(specifications);
    }
}

一个可能的解决方案：我正在考虑添加一个引用被审计实体的新实体，如下所示：

@Entity @Table(name = "audit_persons")
public class AuditedPerson {
       private String id;
       private Integer rev;
       private Integer revtype;
       private String username;
       /*getters and setters*/
}

然后我的方法是

public static Specification<Person> findByUsername(final String username) {
       return new Specification<Person>() {
           @Override
           public Predicate toPredicate(Root<Person> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
               Join<Person, AuditedPerson> joinAudit = root.join(id, JoinType.LEFT);
               return cb.and(cb.equal(joinAudit.get("username"), username),
                               cb.equal(joinAudit.get("revtype"), 0)); //this is so I get the creation instance's username
           }
       };
   }

我会努力完成这项工作。有没有办法做到这一点？我应该只添加一个执行此操作的本机查询吗？谢谢！

4

2 回答 2

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One solution would be to use JPA @SecondaryTable with a database view.

Firstly, create a view (say vw_person_additional_data) from the audit table that selects only the initial 'created' record for each Person.

Update your person Entity as below. The @SecondaryTable annotation lets us map an Entity to one or more tables or views.

@Entity 
@Table(name = "persons")
@Audited 
@AuditTable(name = "audit_persons")
//secondary table referencing our new view
@SecondaryTable(name = "vw_person_additional_data", 
                   pkJoinColumns = {@PrimaryKeyJoinColumn(name = "person_id", 
                        referencedColumnName = "id")}) 
public class Person {
        private String id;
        private String name;
        private Job job;

        @Column(name = "username", table="vw_person_additional_data") //column in view
        private String createdBy;
}

The createdBy property is now just like any other property of Person when it comes to writing specifications.

于 2020-02-19T09:48:30.000 回答
0

最后，我找不到正确引用审计表的方法，所以不得不使用 hibernate enver 来访问它。我不会将此标记为答案，因为它不符合我的要求，但我仍然会添加它，以便我知道我做了什么。我所做的（供将来参考）如下：

@Transactional(isolation = Isolation.READ_UNCOMMITTED, propagation = Propagation.REQUIRED, readOnly = true)
public Map<Long,String> getCreatorUsernameByPersonId(List<Long> personIds) {

    Map<Long,String> result = new HashMap<Long,String>();
    EntityManager em = entityManagerFactory.createEntityManager();
    List<?> auditedPeople = null;
    try {
        AuditReader reader = AuditReaderFactory.get(em);
        AuditQuery query = reader.createQuery().forRevisionsOfEntity(Person.class, false, false);
        if(personIds != null && !personIds.isEmpty()) query.add(AuditEntity.id().in(personIds));
        query.add(AuditEntity.revisionType().eq(RevisionType.ADD));
        auditedPeople = query.getResultList();
        if(auditedPeople != null && !auditedPeople.isEmpty()){
            for(Object o : auditedPeople) {
                result.put(((Person)((Object[])o)[0]).getId(), ((AuditRevEntity)((Object[])o)[1]).getUsername());
            }
        }
    } finally {
        em.close();
    }
    return result;
}

然后我在为我需要的创建 dto 时使用了该哈希图。

于 2020-03-06T18:27:34.427 回答