0

我有一个 xml 值

<ITEMS>
<ITEM><ID>1</ID><NAME>John</NAME></ITEM>
<ITEM><ID>5</ID><NAME>James</NAME></ITEM>
</ITEMS>

我可以使用以下查询将上述 xml 分解为 ID 和名称列的表

Declare @X xml
select x.r.value('(ID)[1]','int') as [ID],
       x.r.value('(DATA)[1]','VARCHAR(100)') AS [DATA]
FROM @X.nodes ('/ITEMS/ITEM') AS x(r)

但是，当上述 xml 连续出现时，我将如何做到这一点。

S.No   COMPANY        DATA
 1      ABC      </ITEMS><ITEM><ID>1</ID><NAME>John</Name>....

我需要填充如下

S.No   COMPANY    ID     NAME
 1      ABC        1    John
 2      ABC        5    James

注意：表中的Data列是varchar数据类型，不是xml数据类型。

4

1 回答 1

0

首先，您可以使用 CTE 将其转换为 XML 数据类型。第二种方式是通过派生表。

SQL

-- DDL and sample data population, start
DECLARE @tbl TABLE (SequentialNo INT PRIMARY KEY, Company VARCHAR(20), [DATA] VARCHAR(MAX));
INSERT INTO @tbl (SequentialNo, Company, [DATA])
VALUES
(1, 'ABC', '<ITEMS>
    <ITEM>
        <ID>1</ID>
        <NAME>John</NAME>
    </ITEM>
    <ITEM>
        <ID>5</ID>
        <NAME>James</NAME>
    </ITEM>
</ITEMS>');
-- DDL and sample data population, end

-- Method #1
-- CTE
;WITH rs AS
(
   SELECT *, TRY_CAST([DATA] AS XML) AS [xmldata]
   FROM @tbl
)
SELECT SequentialNo
    , Company
    , col.value('(ID/text())[1]','INT') AS ID
    , col.value('(NAME/text())[1]','VARCHAR(40)') AS [Name]
FROM rs AS tbl
    CROSS APPLY tbl.[xmldata].nodes('/ITEMS/ITEM') AS tab(col);

-- Method #2
-- Derived table
SELECT SequentialNo
    , Company
    , col.value('(ID/text())[1]','INT') AS ID
    , col.value('(NAME/text())[1]','VARCHAR(40)') AS [Name]
FROM (SELECT *, TRY_CAST([DATA] AS XML) AS [xmldata]
   FROM @tbl) AS tbl
    CROSS APPLY tbl.[xmldata].nodes('/ITEMS/ITEM') AS tab(col);

输出

+--------------+---------+----+-------+
| SequentialNo | Company | ID | Name  |
+--------------+---------+----+-------+
|            1 | ABC     |  1 | John  |
|            1 | ABC     |  5 | James |
+--------------+---------+----+-------+
于 2020-02-17T12:58:52.753 回答