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我正在关注 React Redux 中的教程。我用 Redux store 创建了一个 store 变量，它有两个子变量。一个是expenses对象数组，另一个是filters对象本身。

const store = createStore(
    combineReducers({
        expenses: expensesReducer,
        filters: filtersReducer
    })
);

当填充虚拟值时，存储将如下所示：

const dummyState = {
    expenses: [{
        id: '10-AC-191',
        title: 'January Rent',
        note: 'This was the final payment for that address',
        amount: 545.00,
        createdAt: 0
    }, {
        id: '10-AK-155',
        title: 'Breakfast',
        amount: 545.00,
        createdAt: 2000
    }],
    filters: {
        text: 'rent',
        sortBy: 'amount',
        startDate: 700,
        endDate: 360,
    }
};

我目前正在编写一个函数来显示如下所示的结果费用数组。

const getVisibleExpenses = (expenses, {text, sortBy, startDate, endDate}) => {
    return expenses.filter(({title, note, createdAt}) => {
        const startDateMatch = typeof startDate !== 'number' || createdAt >= startDate;
        const endDateMatch = typeof endDate !== 'number' || createdAt <= endDate;

        const searchText = text.trim().toLowerCase();
        const textMatch = typeof text !== 'string' || title.toLowerCase().includes(searchText)
            || note.toLowerCase().includes(searchText);

        return startDateMatch && endDateMatch && textMatch;
    }).sort((expense_a, expense_b) => {
        if (sortBy === 'amount') return expense_a.amount - expense_b.amount;
        else if (sortBy === 'date') return expense_a.createdAt - expense_b.createdAt;
    });
};

该函数将store.expenses,store.filters作为两个输入。所以我只想传入store对象并获得输出。

因此，我尝试对输入存储本身进行对象解构，而不是在下面调用存储。但它返回一个错误。

const getVisibleExpenses = ({expenses, {text, sortBy, startDate, endDate}})

有没有可能的解决方案？

4

1 回答 1

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尝试这个：

const getVisibleExpenses = ({expenses, filters: {text, sortBy, startDate, endDate}}) => {}
于 2020-02-18T22:52:10.980 回答