我在提供的计算机上编写了这段代码:
factor_in_inches(Unit, Scale) :- scale_of(Unit, Scale, inch).
scale_factor(Unit1, Unit2, Factor) :- scale_of(Unit2, Factor, Unit1).
%PartI
scales(BigUnit, Scale, LittleUnit) :-
scale(BigUnit, Scale, LittleUnit);
scale(LittleUnit, Scale1, BigUnit),
Scale is 1/Scale1.
%check if input follow base or reverse predicate
scale_of(BigUnit, Scale, LittleUnit) :-
scales(BigUnit, Scale, LittleUnit);
scales(BigUnit, Scale1, LittleUnit1),
scale_of(LittleUnit1, Scale2, LittleUnit),
Scale is Scale1 * Scale2.
%Checks if Unit1 * Quantity1 = Unit2 * Quantity2
convert(Unit1, Quantity1, Unit2, Quantity2) :-
factor_in_inches(Unit1, Scale1),
factor_in_inches(Unit2, Scale2),
Scale1 is round(Scale2 * Quantity2 / Quantity1).
我正在尝试为我的家庭作业运行一个小测试用例,如下所示:
:- begin_tests(imperial_part1).
test(factor_in_inches) :- factor_in_inches(inch, 1.0).
test(factor_in_inches) :- factor_in_inches(foot, 12.0).
test(factor_in_inches) :- factor_in_inches(rod, 198.0).
:- end_tests(imperial_part1).
但是,每当我运行测试时,都会收到以下错误:
ERROR: /Users/brianpattison/Desktop/Semester_2/Progamming_Languages/Prolog/SWI-Prolog.app/Contents/MacOS/imperial_hw.pl:67:
test factor_in_inches: received error: plunit_imperial_part1:'unit body'/2: Undefined procedure: plunit_imperial_part1:factor_in_inches/2
However, there are definitions for:
factor_in_inches/2
ERROR: /Users/brianpattison/Desktop/Semester_2/Progamming_Languages/Prolog/SWI-Prolog.app/Contents/MacOS/imperial_hw.pl:68:
test factor_in_inches: received error: plunit_imperial_part1:'unit body'/2: Undefined procedure: plunit_imperial_part1:factor_in_inches/2
However, there are definitions for:
factor_in_inches/2
ERROR: /Users/brianpattison/Desktop/Semester_2/Progamming_Languages/Prolog/SWI-Prolog.app/Contents/MacOS/imperial_hw.pl:69:
test factor_in_inches: received error: plunit_imperial_part1:'unit body'/2: Undefined procedure: plunit_imperial_part1:factor_in_inches/2
However, there are definitions for:
factor_in_inches/2
我已经尝试了很多次来解决这个问题,但我无法做到。
有什么建议么?