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我正在尝试使用 Hibernate Validator 将验证添加到我的表单到我的项目中。在提交以下页面时，会显示错误消息。但是，当我从 Controller ( UserController.handleLogin ) 方法中删除@Valid注释时，我可以提交详细信息。有人可以建议我错过什么吗？

在提交登录表格时

用户控制器.java

@Controller
public class UserController {   

@RequestMapping(value = { "/", "/index" })
public String index(Model model) {
    model.addAttribute("command", new LoginCommand());
    return "index";
}

@RequestMapping(value = "/login", method = RequestMethod.GET)
public String handleLogin(Model model) {
    model.addAttribute("err", null);
    return "redirect:index";
}

@RequestMapping(value = "/login", method = RequestMethod.POST)
public String handleLogin(@Valid @ModelAttribute("command") LoginCommand cmd, Model model, HttpSession session, Errors error) {
    if(error.hasErrors()) {
        return "index";
    }
    try {
        User loggedInUser = userService.doLogin(cmd.getLoginName(), cmd.getPassword());
        if (loggedInUser == null) {
            model.addAttribute("err", "Login failed, enter valid credentials");
            return "index";
        } else {

            if (loggedInUser.getRole().equals(UserService.ROLE_ADMIN)) {
                // add user to session
                addUserToSession(loggedInUser, session);
                return "redirect:admin/dashboard";
            } else if (loggedInUser.getRole().equals(UserService.ROLE_USER)) {
                // add user to session
                addUserToSession(loggedInUser, session);
                return "redirect:user/dashboard";
            } else {
                model.addAttribute("err", "Invalid User Role");
                return "index";
            }
        }
    } catch (UserBlockedException e) {
        model.addAttribute("err", e.getMessage());
        return "index";
    }
}
}

登录命令.java

public class LoginCommand {

    @Size(max = 20, min = 3, message = "Login Name must be between 3 and 20 characters")
    private String loginName;

    @Size(max = 20, min = 3, message = "Password cannot be empty")
    private String password;

    public String getLoginName() {
        return loginName;
    }

    public void setLoginName(String loginName) {
        this.loginName = loginName;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

}

索引.jsp

<s:url var="url_login" value="/login"></s:url>
<f:form action="${url_login}" modelAttribute="command" valign="middle" method="POST">
    <table border="1" align="center" width="40%">
        <thead>
            <tr>
                <td colspan="2" valign="middle" align="center">
                    <h2>Login here</h2></td>
            </tr>
        </thead>
        <tbody>
            <tr>
                <td align="center">Username: </td>
                <td align="center">
                    <f:input path="loginName" placeholder="Enter your username"/>
                    <f:errors path="loginName" />
                </td>
            </tr>
            <tr>
                <td align="center">Password: </td>
                <td align="center">
                    <f:password path="password" placeholder="Enter your password"/>
                    <f:errors path="password"/>
                </td>
            </tr>
            <tr>
                <td colspan="2" align="center">
                    <f:button>Login</f:button>
                    <a href="${url_reg_form}" class="newReg">New User Registration</a>
                </td>
            </tr>
        </tbody>
    </table>
</f:form>
4

1 回答 1

0

将绑定结果添加到您的方法中。

绑定结果绑定结果

于 2020-02-10T15:35:54.333 回答