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TL;DR：为什么关闭收到 SIGPIPE 异常的 fifo 文件（命名管道）会产生另一个 SIGPIPE 异常？

我的 python 脚本正在通过 FIFO 文件将字节写入另一个进程，该进程是我的 python 进程的子进程。（有一些限制，我必须使用命名管道。）

我必须考虑到子进程可能会提前终止的事实。如果发生这种情况，我的 python 脚本必须获取死子进程并重新启动它。

要查看子进程是否死亡，我只是先尝试​​写入 FIFO，如果我得到一个 SIGPIPE 异常（实际上是 IOError 表示管道损坏），我知道是时候重新启动我的子进程了。

最小的例子如下：

#!/usr/bin/env python3
import os
import signal
import subprocess

# The FIFO file.
os.mkfifo('tmp.fifo')

# A subprocess to simply discard any input from the FIFO.
FNULL = open(os.devnull, 'w')
proc = subprocess.Popen(['/bin/cat', 'tmp.fifo'], stdout=FNULL, stderr=FNULL)
print('pid = %d' % proc.pid)

# Open the FIFO, and MUST BE BINARY MODE.
fifo = open('tmp.fifo', 'wb')

# Endlessly write to the FIFO.
while True:

    # Try to write to the FIFO, restart the subprocess on demand, until succeeded.
    while True:
        try:
            # Optimistically write to the FIFO.
            fifo.write(b'hello')
        except IOError as e:
            # The subprocess died. Close the FIFO and reap the subprocess.
            fifo.close()
            os.kill(proc.pid, signal.SIGKILL)
            proc.wait()

            # Start the subprocess again.
            proc = subprocess.Popen(['/bin/cat', 'tmp.fifo'], stdout=FNULL, stderr=FNULL)
            print('pid = %d' % proc.pid)
            fifo = open('tmp.fifo', 'wb')
        else:
            # The write goes on well.
            break

要重现结果，请运行该脚本并手动终止子进程kill -9 <pid>。回溯会告诉你

Traceback (most recent call last):
  File "./test.py", line 24, in <module>
    fifo.write(b'hello')
BrokenPipeError: [Errno 32] Broken pipe

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "./test.py", line 27, in <module>
    fifo.close()
BrokenPipeError: [Errno 32] Broken pipe

那么为什么关闭 FIFO 文件会产生另一个 SIGPIPE 异常呢？

我在以下平台上进行了测试，结果是一样的。

Python 3.7.6 @ Darwin Kernel Version 19.3.0 (MacOS 10.15.3)
Python 3.6.8 @ Linux 4.18.0-147.3.1.el8_1.x86_64 (Centos 8)
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1 回答 1

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这是因为 Python 在失败时不会清除写缓冲区fifo.write。所以缓冲区会在执行时再次写入损坏的管道fifo.close，这会导致第二次SIGPIPE。

我在 的帮助下找到了原因strace。这里有一些细节。

首先，修改一小部分 Python 代码，如下所示，

#!/usr/bin/env python3
import os
import signal
import subprocess

# The FIFO file.
os.mkfifo('tmp.fifo')

# A subprocess to simply discard any input from the FIFO.
FNULL = open(os.devnull, 'w')
proc = subprocess.Popen(['/bin/cat', 'tmp.fifo'], stdout=FNULL, stderr=FNULL)
print('pid = %d' % proc.pid)

# Open the FIFO, and MUST BE BINARY MODE.
fifo = open('tmp.fifo', 'wb')

i = 0
# Endlessly write to the FIFO.
while True:

    # Try to write to the FIFO, restart the subprocess on demand, until succeeded.
    while True:
        try:
            # Optimistically write to the FIFO.
            fifo.write(f'hello{i}'.encode())
            fifo.flush()
        except IOError as e:
            # The subprocess died. Close the FIFO and reap the subprocess.
            print('IOError is occured.')
            fifo.close()
            os.kill(proc.pid, signal.SIGKILL)
            proc.wait()

            # Start the subprocess again.
            proc = subprocess.Popen(['/bin/cat', 'tmp.fifo'], stdout=FNULL, stderr=FNULL)
            print('pid = %d' % proc.pid)
            fifo = open('tmp.fifo', 'wb')
        else:
            # The write goes on well.
            break
    os.kill(proc.pid, signal.SIGKILL)
    i += 1

并将其另存为test.py.

然后strace -o strace.out python3 test.py在shell中运行。检查一下strace.out，我们可以找到类似的东西

openat(AT_FDCWD, "tmp.fifo", O_WRONLY|O_CREAT|O_TRUNC|O_CLOEXEC, 0666) = 4
fstat(4, {st_mode=S_IFIFO|0644, st_size=0, ...}) = 0
ioctl(4, TCGETS, 0x7ffcba5cd290)        = -1 ENOTTY (Inappropriate ioctl for device)
lseek(4, 0, SEEK_CUR)                   = -1 ESPIPE (Illegal seek)
write(4, "hello0", 6)                   = 6
kill(35626, SIGKILL)                    = 0
write(4, "hello1", 6)                   = 6
kill(35626, SIGKILL)                    = 0
write(4, "hello2", 6)                   = -1 EPIPE (Broken pipe)
--- SIGPIPE {si_signo=SIGPIPE, si_code=SI_USER, si_pid=35625, si_uid=1000} ---
--- SIGCHLD {si_signo=SIGCHLD, si_code=CLD_KILLED, si_pid=35626, si_uid=1000, si_status=SIGKILL, si_utime=0, si_stime=0} ---
write(1, "IOError is occured.\n", 20)   = 20
write(4, "hello2", 6)                   = -1 EPIPE (Broken pipe)
--- SIGPIPE {si_signo=SIGPIPE, si_code=SI_USER, si_pid=35625, si_uid=1000} ---
close(4)                                = 0
write(2, "Traceback (most recent call last"..., 35) = 35
write(2, "  File \"test.py\", line 26, in <m"..., 39) = 39

请注意，Python 尝试编写hello2两次，期间fifo.flush和fifo.close分别。输出解释了为什么会很好地生成两个 SIGPIPE 异常。

为了解决这个问题，我们可以使用open('tmp.fifo', 'wb', buffering=0)禁用写缓冲区。那么只会产生一个 SIGPIPE 异常。

于 2020-02-07T12:08:55.773 回答