我正在制作一个函数来返回小数位数和整数位数,并typename
使用 s 将插入的数字转换为字符串sstream
。
但是,转换为字符串时的数字以科学计数法出现,这对于计算正常数字的位数没有用。如何在下面的函数中阻止这种情况发生?
enum { DECIMALS = 10, WHOLE_NUMBS = 20, ALL = 30 };
template < typename T > int Numbs_Digits(T numb, int scope)
{
stringstream ss(stringstream::in | stringstream::out);
stringstream ss2(stringstream::in | stringstream::out);
unsigned long int length = 0;
unsigned long int numb_wholes;
ss2 << (int) numb;
numb_wholes = ss2.str().length();
ss2.flush();
bool all = false;
switch (scope) {
case ALL:
all = true;
case DECIMALS:
ss << numb;
length += ss.str().length() - (numb_wholes + 1); // +1 for the "."
if (all != true)
break;
case WHOLE_NUMBS:
length += numb_wholes;
if (all != true)
break;
default:
break;
}
return length;
}