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有人可以帮助正确的方法或对此有意见。我已经编写了下面的代码,该代码应该从文本文件中获取输入,按顺序排列一行,并声明这是最小数字,然后在下一行相同的最大数字,最后是所有数字的平均值。

我的代码:

from statistics import mean
def number1():
    with open('input.txt') as file:
    data = {line.split(':')[0]: sorted([int(value) for value in line.split(':')[1].split(',')]) for line in file.readlines()}
    functions = {'min': min, 'max': max, 'avg': mean}
with open('output.txt', 'w') as file:
     file.writelines(f"The {function} of {values} is {functions[function](values)}\n" for function, values in data.items())
number1()

有人告诉我这是不正确的。下面是建议我应该使用的代码,但在清除我认为正确的缩进之后。我只得到平均线的输出。

建议代码:

outfile = open("output.txt", "w")

with open("input.txt") as f:
    for line in f:
        # clean line and split into operator and data
        operator, data = line.lower().strip().split(":")

    line = line.split(":")
    operator = line[0].lower().strip()
    data = line[1].strip().split(",")

        # parse data into list of integers
        # data = [int(x) for x in data.split(",")]
        # convert numbers in list to integer
    newData = []

    for x in data:
          newData.append(int(x))

        # min(), max(), sum(), len()
        # determine operation to perform on number list variable
    if operator == "min":
            result = min(newData)
    elif operator == "max":
            result = max(newData)
    elif operator == "avg":
            result = sum(newData) / len(newData)

        # create output string
    report_line = "The {} of {} is {}.\n".format(operator, newData, result)
    outfile.write(report_line)
outfile.close()        
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1 回答 1

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您可以使用以下逻辑。

假设您的文本文件是 data.txt ,内容如下

3 7 5 
0 4 2 
8 1 6 

2 6 3 
1 0 8 
5 4 7 

4 1 6 
0 8 7 
2 3 5 

7 2 6 
4 1 3 
8 0 5 

使用下面的代码将所有数字插入列表并找到最小值和最大值。

list = []
file = open('data.txt', 'r')
for line in file.readlines():
    for n in line:
        if (n!=" " and  n!="\n"):
            list.append(n)
print(list)
print(min(list),max(list))
于 2020-02-05T13:05:39.883 回答