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这是我的第一个问题，我会尽量说清楚。如果之前有人问过类似的问题，请原谅我（我检查过但一无所获）。

我正在尝试在 java 中创建我的第一个 android 应用程序。这是一个小游戏，屏幕左侧有一个角色（横向模式），背景从右到左，给人以运动的印象。背景的速度是恒定的。我使用了一个如下所示的背景类：

public class Background {

    int x=0, y=0;
    Bitmap background;

    Background(int screenX, int screenY, Resources res){

        background = BitmapFactory.decodeResource(res, R.drawable.background);
        background = Bitmap.createScaledBitmap(background, screenX, screenY, false);
    }
}

然后在 GameView 类中创建 2 个背景对象

private Background background1, background2;

在构造函数中：

background1 = new Background(screenX, screenY, getResources());
background2 = new Background(screenX, screenY, getResources());

//both backgrounds are the same picture

background2.x = screenX;

paint= new Paint();

最后：

private void update(){
    background1.x -=2 * screenRatioX;
    background2.x -=2 * screenRatioX;
    //both have the same speed

    if (background1.x + background1.background.getWidth()<0){
        background1.x = screenX;
        // to make it reappear on the right side when it vanishes on the left side
    }
    if (background2.x + background2.background.getWidth()<0){
        background2.x = screenX;
    }
}

我希望这很清楚，并且有人能够帮助我。

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1 回答 1

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编辑：我实际上是通过给出 background2 相对于 background1 位置的轴位置来解决它

private void update(){
background1.x =(int)(background1.x - (2 * screenRatioX));
if(background1.x < background2.x) {
        background2.x = background1.x + background1.background.getWidth();}
        //(int)(background2.x - (2 * screenRatioX));
else {background2.x =background1.x-background1.background.getWidth();




    }

if (background1.x + background1.background.getWidth()<0){
    background1.x = background2.x + background2.background.getWidth();

}
if (background2.x + background2.background.getWidth()<0){
    background2.x = background1.x+background1.background.getWidth();
    }

我仍然有兴趣了解为什么会发生这种情况。谢谢你们

于 2020-02-05T12:30:13.543 回答