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我有以下 OPL 代码，需要在 docplex (python) 中实现它，我是该领域的新手......

using CP;
dvar interval I1 in 0..20;
dvar interval I2 in 0..20;
dvar interval I3 in 0..20;

dvar int over1;
dvar int start1;
dvar int end1;

dvar interval artificialInterval;

maximize over1;

subject to
{

    over1==overlapLength(I1,I2);

    start1==maxl(startOf(I1),startOf(I2));

    end1==minl(endOf(I1),endOf(I2));

    startOf(artificialInterval)==start1;
    endOf(artificialInterval)==end1;

    over1==overlapLength(I3,artificialInterval);
}

问题出现在行 startOf(artificialInterval)==start1; 和 endOf(artificialInterval)==end1;

这是我所做的：

mdl=CpoModel()

   I1=mdl.interval_var(define its parameters)
   I2=mdl.interval_var(define its parameters)
   I3=mdl.interval_var(define its parameters)

   over1=mdl.integer_var()
   start1=mdl.integer_var()
   end1=mdl.integer_var()

   artificialInterval=mdl.interval_var()

   over1=mdl.overlapLength(I1,I2)
   start1=mdl.max(mdl.start_of(I1),mdl.start_of(I2))
   end1=mdl.min(mdl.end_of(I1),mdl.end_of(I2))

   mdl.start_of(artificialInterval) =start1
   mdl.end_of(artificialInterval) =end1

   over1=mdl.overlapLength(I3,artificialInterval)

   obj = mdl.maximize(over1)
   mdl.solve()

有了这个我有语法错误“SyntaxError：无法分配给函数调用”所以我尝试使用 set_start(start1) 但我认为我也没有很好地使用它......

任何提示表示赞赏。谢谢，

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1 回答 1

1 
from docplex.cp.model import CpoModel 
mdl=CpoModel()

I1=mdl.interval_var(0,10)
I2=mdl.interval_var(0,10)
I3=mdl.interval_var(0,10)

over1=mdl.integer_var()
start1=mdl.integer_var()
end1=mdl.integer_var()

artificialInterval=mdl.interval_var()

mdl.add(over1==mdl.overlap_length(I1,I2))
start1=mdl.max(mdl.start_of(I1),mdl.start_of(I2))
end1=mdl.min(mdl.end_of(I1),mdl.end_of(I2))

mdl.add(mdl.start_of(artificialInterval) ==start1)
mdl.add(mdl.end_of(artificialInterval) ==end1)

mdl.add(over1==mdl.overlap_length(I3,artificialInterval))

obj = mdl.maximize(over1)
mdl.solve()

效果更好

于 2020-02-05T10:50:09.183 回答