2

我有一个 Java 小程序，它将由用户必须与之交互的几个弹出菜单组成。但是，JPopupMenu 在添加时不会显示。这是我的代码：

public class Parser extends JApplet implements ActionListener {
    private static final long serialVersionUID = 1L;
    JPopupMenu deviceMenu;
    JButton downloadButton;
    Map <String, Object> deviceDict;

    public void init () {
        try {
            SwingUtilities.invokeAndWait(new Runnable() {
                public void run() {
                    createGUI();
                }
            });
        } 
        catch (Exception e) { 
            System.err.println("createGUI didn't successfully complete");
        }
    }
    public void createGUI() {
        try {
            URL url = new URL("[URL]");
            URLConnection conn = url.openConnection();
            BufferedReader in = new BufferedReader(
                                    new InputStreamReader(
                                    conn.getInputStream()));
            String inputLine;
            String xml = "";
            while ((inputLine = in.readLine()) != null) 
                xml = xml + inputLine;
        deviceDict = Plist.fromXml(xml);
        System.out.print(deviceDict);
        } 

        catch (XmlParseException e) {
            e.printStackTrace();
        } 
        catch (IOException e) {
            e.printStackTrace();
        }
        setLayout(new FlowLayout());
        setPreferredSize(new Dimension(480, 360));
        setSize(480, 360);
        Iterator <String> deviceIterator = deviceDict.keySet().iterator();
        deviceMenu = new JPopupMenu("Test");
        while (deviceIterator.hasNext()) {
            JMenuItem item = new JMenuItem(deviceIterator.next());
            deviceMenu.add(item);
        }
        add(deviceMenu);
    }
}

任何想法为什么？

4

2 回答 2

3

你希望它什么时候出现？如果要显示弹出菜单，则
需要调用show() 。
请参阅此示例和来自 oracle 站点的示例。

顺便说一句 - 从你的问题看来JDialog

于 2011-05-14T20:59:08.243 回答
0

不得不使用 JComboBox 而不是 JPopupMenu

于 2011-06-02T23:11:16.220 回答