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我正在制作一个应用程序，该应用程序包含一个带有许多交易的钱包的用户配置文件。

这是事务类：

@Entity
@Table(name = "transactions")
public class Transaction extends BaseEntity {

    @Column(name = "amount", nullable = false)
    private BigDecimal amount;

    @Column(name = "executed_on", nullable = false)
    private LocalDateTime executedOn;

    @Column(name = "is_top_up")
    private boolean isTopUp;

    @Column(name = "note")
    private String note;

    @ManyToOne(targetEntity = UserProfile.class)
    private UserProfile sender;

    @ManyToOne(targetEntity = UserProfile.class)
    private UserProfile receiver;

    public Transaction() {
    }

这是钱包类

@Entity
@Table(name = "wallets")
public class Wallet extends BaseEntity {

    @ManyToMany(targetEntity = Transaction.class, cascade = {
            CascadeType.PERSIST,
            CascadeType.MERGE
    }, fetch = FetchType.EAGER)
    @JoinTable(name = "wallets_transactions",
            joinColumns = @JoinColumn(name = "wallet_id", referencedColumnName = "id"),
            inverseJoinColumns = @JoinColumn(name = "transaction_id", referencedColumnName = "id")
    )
    private Set<Transaction> transactions;

    public Wallet() {
        this.transactions = new HashSet<>();
    }

    public Set<Transaction> getTransactions() {
        return transactions;
    }

    public void setTransactions(Set<Transaction> transactions) {
        this.transactions = transactions;
    }

    public void addTransaction(Transaction transaction) {
        this.transactions.add(transaction);
    }
}

我想要的是，通过发送方和接收方搜索条件获取所有交易。例如，用户“A”向用户“B”汇款。我正在使用 JpaRepository。最终结果应该在一个Page<Transaction>类中。

到目前为止，当使用 just 时findAllBySender(UserProfile sender, Pageable pageable)，它确实有效，并且我得到了完全正确的交易。但是当我尝试时，当我的数据库具有至少 1 条记录的测试数据时，Page<Transaction> findAllBySenderAndReceiver(UserProfile sender, UserProfile receiver, Pageable pageable);我得到了0 个元素。Page<T>

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1 回答 1

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解决了。事实证明，我有一个逻辑错误。谢谢大家，你们的帮助。

于 2020-01-27T09:23:26.773 回答