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我有一段代码在调用 notifyAll 时给出 IllegalMonitorException。在 enQueue() 时，线程添加数据并抛出非法监视器异常。

BlockingQueue.class ：

public class BlockingQueue {
private Queue<Integer> queue = new LinkedList<>();
private int maxCount;
private Lock lock = new ReentrantLock();

BlockingQueue(int maxCount){
    this.maxCount=maxCount;
}

public  void enQueue(int d) throws InterruptedException {
    lock.lock();
    if(queue.size() >= maxCount){
        System.out.println("going to wait enqueu "+Thread.currentThread().getName() +" size "+queue.size());
        lock.wait();
    }
    System.out.println(" Adding "+d);
    queue.add(d);
    lock.notify();
    lock.unlock();
}

public  Integer deQueue() throws InterruptedException {
    lock.lock();
    if(queue.size()==0){
        System.out.println("going to wait dequeue "+Thread.currentThread().getName()+" size "+queue.size());
        lock.wait();
    }
    int data = queue.remove();
    lock.notify();
    lock.unlock();
    return data;
}}

主类：

 public class Main {
public static void main(String args[]){
    BlockingQueue queue=new BlockingQueue(10);
    Producer p = new Producer(queue);
    Consumer c = new Consumer(queue);

    Thread t1=new Thread(c,"Consumer");
    Thread t2=new Thread(p, "producer");

    t1.start();
    t2.start();
}}

生产者类：

 public class Producer implements Runnable {
private BlockingQueue q;
Producer(BlockingQueue qu){
    this.q=qu;
}

public Integer generateWork() throws InterruptedException {
    return new Random().nextInt(100 );
}

@Override
public void run() {
    for(int i =0; i<100; i++){
        try {
            Thread.sleep(100);
            q.enQueue(generateWork());
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }
}}

消费者类：

public class Consumer implements Runnable {

private BlockingQueue queue;
Consumer(BlockingQueue q){
    this.queue=q;
}

public void consume(int data){
    System.out.println(" consume "+data);
}

@Override
public void run() {
    for(int i=0; i < 100; i++){
        try {
            Thread.sleep(1000);
            consume(queue.deQueue());
        } catch (InterruptedException e) {
           System.out.println("interrupted");
        }
    }
}}

输出 ：

添加 94

线程“生产者”java.lang.IllegalMonitorStateException 中的异常

at java.lang.Object.notify(Native Method)
at BlockingQueue.enQueue(BlockingQueue.java:23)
at Producer.run(Producer.java:20)
at java.lang.Thread.run(Thread.java:748)
4

1 回答 1

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以下代码修复了问题

public class BlockingQueue {
    private Queue<Integer> queue = new LinkedList<>();
    private int maxCount;
    private Lock lock = new ReentrantLock();

    BlockingQueue(int maxCount) {
        this.maxCount = maxCount;
    }

    public void enQueue(int d) throws InterruptedException {
        lock.lock();
        if (queue.size() >= maxCount) {
            System.out.println("going to wait enqueu " + Thread.currentThread().getName() + " size " + queue.size());
            waitInternal();
        }
        System.out.println(" Adding " + d);
        queue.add(d);
        notifyInternal();
        lock.unlock();
    }

    public Integer deQueue() throws InterruptedException {
        lock.lock();
        if (queue.size() == 0) {
            System.out.println("going to wait dequeue " + Thread.currentThread().getName() + " size " + queue.size());
            waitInternal();
        }
        int data = queue.remove();
        notifyInternal();
        lock.unlock();
        return data;
    }

    private void waitInternal() throws InterruptedException {
        synchronized (lock) {
            lock.wait();
        }
    }

    private void notifyInternal() throws InterruptedException {
        synchronized (lock) {
            lock.notify();
        }
    }
}

解释：您从不允许的非同步块调用waitand 。notify当您调用其中任何一个时，您应该对该对象进行监视器锁定。在这种情况下lock。

这是关于为什么必须等待/通知始终在同步块中的精彩读物 https://stackoverflow.com/a/2779565/1891456

于 2020-01-25T07:06:21.483 回答