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对于初学者，这是我正在使用的表结构：

df <- structure(list(customer_id = c(353808874L, 69516747L, 357032052L, 
307735090L, 307767260L), id = c("8474", "8107", 
"1617436", "7698", "1617491"), lon1 = c(-115.032623, -115.155029, 
-115.270386, -115.19426, -115.177589), lat1 = c(36.0437202, 36.1366234, 
36.1678734, 36.2635803, 36.2218285), lon2 = c(-115.037022076035, 
-115.150112230012, -115.27341017806, -115.193072645577, -115.174902476442
), lat2 = c(36.0410001245783, 36.141137860928, 36.1700923382169, 
36.2682687632778, 36.2240270452917)), row.names = c(NA, 5L), class = "data.frame")

我尝试使用来自几个不同 Stack Overflow 问题的信息，但没有一个达到预期的结果。

其中之一是：

earthDist <- function (lon1, lat1, lon2, lat2){
    rad <- pi/180
    a1 <- lat1 * rad
    a2 <- lon1 * rad
    b1 <- lat2 * rad
    b2 <- lon2 * rad
    dlon <- b2 - a2
    dlat <- b1 - a1
    a <- (sin(dlat/2))^2 + cos(a1) * cos(b1) * (sin(dlon/2))^2
    c <- 2 * atan2(sqrt(a), sqrt(1 - a))
    R <- 6378.145
    d <- R * c
    return(d)
}

earthDist(lon[1], lat[1], lon, lat)

但我无法让它产生我正在寻找的输出。我当然不依附它，所以如果有人有更有效的东西，我全神贯注！

编辑：我的预期结果相当简单。只有三列，distance_between代表 lon/lat1 和 lon/lat2 之间的距离：

+-------------+----+------------------+
| customer_id | id | distance_between |
+-------------+----+------------------+
4

1 回答 1

2

这很容易通过distGeogeosphere 包中的函数（类似于上面的函数）解决：

library(geosphere)
#calculate distances in meters
df$distance<-distGeo(df[,c("lon1", "lat1")], df[,c("lon2", "lat2")])

#remove columns
df[, -c(3:6)]

customer_id      id distance
1   353808874    8474 498.2442
2    69516747    8107 668.4088
3   357032052 1617436 366.9541
4   307735090    7698 531.0785
5   307767260 1617491 343.3051
于 2020-01-22T21:29:22.587 回答