4

我正在尝试获取存储库中的问题数量，但下面的代码正在返回问题和拉取请求。我如何才能得到问题？我想我在这里遗漏了一些简单的东西。我阅读了 api 文档，它指出 GitHub 将所有拉取请求视为问题。

repo = g.get_repo("someRepo")
label = repo.get_label('someLabel')
myIssues = repo.get_issues(state='open',labels=[label])
count = 0
for issue in myIssues:
    count = count + 1
print(count)
4

1 回答 1

2

对于只是问题的问题，pull_requestis None。

>>> repo = g.get_repo("PyGithub/PyGithub")
>>> open_issues = repo.get_issues(state='open')
>>> for issue in open_issues:
...     print(issue)
...
Issue(title="Correct Repository.create_git_tag_and_release()", number=1362)
Issue(title="search_topics returns different number of repositories compared to searching in browser.", number=1352)
>>> print(open_issues[0].pull_request)
<github.IssuePullRequest.IssuePullRequest object at 0x7f320954cb70>
>>> print(open_issues[1].pull_request)
None
>>>

所以你可以只计算那些 issue.pull_request 是的问题None。

repo = g.get_repo("someRepo")
label = repo.get_label('someLabel')
myIssues = repo.get_issues(state='open',labels=[label])
count = 0
for issue in myIssues:
    if not issue.pull_request:
       count = count + 1
print(count)

您还可以按如下方式替换计数逻辑：

count = sum(not issue.pull_request for issue in myIssues)
于 2020-01-21T18:35:35.930 回答