我想为网格内的搜索算法(BFS、A* 等)构建一些可视化。
我的解决方案应该使用 CodeSkulptor (或使用.)simplegui
的离线版本显示算法的每个步骤SimpleGUICS2Pygame
我制作了一个版本,通过更改颜色突出显示所有访问过的单元格,但是我在尝试逐步显示路径时遇到了麻烦,每个步骤之间都有时间延迟。
我已经提取了问题的本质,并在下面的代码中创建了一个代表它的最小示例,也可以在这里在线运行:http: //www.codeskulptor.org/#user47_jB2CYfNrH2_2.py
我想要的是在change_colors()
函数期间,因为每次迭代之间会有延迟。CodeSkulptor 没有time.sleep()
可用的,而且我认为它无论如何也无济于事。
CodeSkulptor 确实有可用的计时器,这可能是一种解决方案,尽管在这种情况下我看不到如何使用它。
下面的代码:
import time
try:
import simplegui
except ImportError:
import SimpleGUICS2Pygame.simpleguics2pygame as simplegui
simplegui.Frame._hide_status = True
TITLE = "TEST"
FRAME_WIDTH = 400
FRAME_HEIGHT = 400
DELAY = 10
class Square:
"""This class represents a simple Square object."""
def __init__(self, size, pos, pen_size=2, pen_color="red", fill_color="blue"):
"""Constructor - create an instance of Square."""
self._size = size
self._pos = pos
self._pen_size = pen_size
self._pen_color = pen_color
self._fill_color = fill_color
def set_color(self, color):
self._fill_color = color
def get_color(self):
return self._fill_color
def is_in(self, pos):
"""
Determine whether coordinates are within the area of this Square.
"""
return self._pos[0] < pos[0] < self._pos[0] + self._size and self._pos[1] < pos[1] < self._pos[1] + self._size
def draw(self, canvas):
"""
calls canvas.draw_image() to display self on canvas.
"""
points = [(self._pos[0], self._pos[1]), (self._pos[0] + self._size, self._pos[1]),
(self._pos[0] + self._size, self._pos[1] + self._size), (self._pos[0], self._pos[1] + self._size)]
canvas.draw_polygon(points, self._pen_size, self._pen_color, self._fill_color)
def __str__(self):
return "Square: {}".format(self._pos)
def draw(canvas):
for square in squares:
square.draw(canvas)
def change_colors():
for square in squares:
# time.sleep(1) # Not implemented in CodeSkulptor and would'nt work anyway
square.set_color("green")
frame = simplegui.create_frame(TITLE, FRAME_WIDTH, FRAME_HEIGHT)
frame.set_draw_handler(draw)
width = 20
squares = []
for i in range(10):
squares.append(Square(width, (i * width, 0)))
change_colors()
frame.start()
任何帮助表示赞赏。