0

我的应用程序在选择image from Pictures或图像类别时完美运行，Gallery但应用程序崩溃时select image from recent images

这是我的意图呼叫

galleryLayout.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            if (EasyPermissions.hasPermissions(getActivity(), perms_gallery)) {
                Intent intent = new Intent();
                intent.setType("image/*");
                intent.putExtra(Intent.EXTRA_ALLOW_MULTIPLE, true);
                intent.setAction(Intent.ACTION_GET_CONTENT);
                startActivityForResult(Intent.createChooser(intent, "Select Picture"), SELECT_FILE);
            }else {
                EasyPermissions.requestPermissions(getActivity(), getString(R.string.read_file),
                        READ_REQUEST_CODE, perms_gallery);
            }
        }
    });

崩溃从这里发生String id = wholeID.split(":")[1];

public String getPathFromUriGallery(Context context, Uri uri) {
    Cursor cursor = null;
    try {
        String wholeID = DocumentsContract.getDocumentId(uri);
        String id = wholeID.split(":")[1];
        String sel = MediaStore.Images.Media._ID + "=?";

        String[] filePath = {MediaStore.Images.Media.DATA};
        cursor = context.getContentResolver().query(MediaStore.Images.Media.EXTERNAL_CONTENT_URI, filePath, sel, new String[]{id}, null);
        cursor.moveToFirst();
        int columnIndex = cursor.getColumnIndex(filePath[0]);
        return  cursor.getString(columnIndex);
    } finally {
        if (cursor != null) {
            cursor.close();
        }
    }
}

这是我的错误日志

Process: io.test.susitkMed.doctor, PID: 9576
java.lang.RuntimeException: Failure delivering result ResultInfo{who=null, request=65537, result=-1, data=Intent { dat=content://com.google.android.apps.docs.storage/document/acc=3;doc=encoded=0ajgvv25pDn5wcNiiiv1YFYu7neaIdrulcWk/kBdEa8TqupNEKLhnLzz flg=0x1 launchParam=MultiScreenLaunchParams { mDisplayId=0 mBaseDisplayId=0 mFlags=0 } }} to activity {io.test.susitkMed.doctor/io.test.susitkMed.doctor.ui.activities.MainActivity}: java.lang.ArrayIndexOutOfBoundsException: length=1; index=1
    at android.app.ActivityThread.deliverResults(ActivityThread.java:4520)
    at android.app.ActivityThread.handleSendResult(ActivityThread.java:4563)
    at android.app.ActivityThread.-wrap22(ActivityThread.java)
    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1698)
    at android.os.Handler.dispatchMessage(Handler.java:102)
    at android.os.Looper.loop(Looper.java:154)
    at android.app.ActivityThread.main(ActivityThread.java:6776)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1496)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1386)
 Caused by: java.lang.ArrayIndexOutOfBoundsException: length=1; index=1
4

4 回答 4

2

我从这个 github 示例https://github.com/maayyaannkk/ImagePicker中找到了这个解决方案

这是上述问题的解决方案

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    if (requestCode == PICK_IMAGE && resultCode == RESULT_OK
            && null != data) {

        Uri selectedImage = data.getData();
        String   imageEncoded = getRealPathFromURI(getActivity(), selectedImageUri);
        Bitmap selectedImage = BitmapFactory.decodeFile(imageString);
        image.setImageBitmap(selectedImage);
    }
}

这些方法用于获取图像 url

public String getRealPathFromURI(Context context, Uri contentUri) {
    OutputStream out;
    File file = new File(getFilename(context));

    try {
        if (file.createNewFile()) {
            InputStream iStream = context != null ? context.getContentResolver().openInputStream(contentUri) : context.getContentResolver().openInputStream(contentUri);
            byte[] inputData = getBytes(iStream);
            out = new FileOutputStream(file);
            out.write(inputData);
            out.close();
            return file.getAbsolutePath();
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
    return null;
}

private byte[] getBytes(InputStream inputStream) throws IOException {
    ByteArrayOutputStream byteBuffer = new ByteArrayOutputStream();
    int bufferSize = 1024;
    byte[] buffer = new byte[bufferSize];

    int len = 0;
    while ((len = inputStream.read(buffer)) != -1) {
        byteBuffer.write(buffer, 0, len);
    }
    return byteBuffer.toByteArray();
}

private String getFilename(Context context) {
    File mediaStorageDir = new File(context.getExternalFilesDir(""), "patient_data");
    // Create the storage directory if it does not exist
    if (!mediaStorageDir.exists()) {
        mediaStorageDir.mkdirs();
    }

    String mImageName = "IMG_" + String.valueOf(System.currentTimeMillis()) + ".png";
    return mediaStorageDir.getAbsolutePath() + "/" + mImageName;

}
于 2020-01-21T06:46:57.427 回答
1

当我从最近选择图像时，图像在 android | 中被破坏 最近的多张图片

我在下面提到了我的答案链接，请去那里找到你的解决方案

您可以从此链接中找到完整的帖子 || 点击此处链接

另外，你可以在这里找到

样品预览

调用多张图片选择

 Intent i = new Intent(Intent.ACTION_GET_CONTENT);
                        i.addCategory(Intent.CATEGORY_OPENABLE);
                        i.setType("image/*");
                        i.putExtra(Intent.EXTRA_ALLOW_MULTIPLE, true);
                        *gallery*.launch(i);

画廊基本上 startActivityForResult(i,123) 和 OnActivityResult 方法已被弃用，画廊是替代品，定义如下

ActivityResultLauncher<Intent> gallery = choosePhotoFromGallery();

并且choosePhotoFromGallery()是下面定义的方法

private ActivityResultLauncher<Intent> choosePhotoFromGallery() {
    return registerForActivityResult(
            new ActivityResultContracts.StartActivityForResult(),
            result -> {
                try {
                    if (result.getResultCode() == RESULT_OK) {
                        if (null != result.getData()) {
                            if (result.getData().getClipData() != null) {
                                ClipData mClipData = result.getData().getClipData();
                                for (int i = 0; i < mClipData.getItemCount(); i++) {
                                    ClipData.Item item = mClipData.getItemAt(i);
                                    Uri uri = item.getUri();
                                    String imageFilePathColumn = getPathFromURI(this, uri);
                                    productImagesList.add(imageFilePathColumn);
                                }
                            } else {
                                if (result.getData().getData() != null) {
                                    Uri mImageUri = result.getData().getData();
                                    String imageFilePathColumn = getPathFromURI(this, mImageUri);
                                    productImagesList.add(imageFilePathColumn);
                                }
                            }
                        } else {
                            showToast(this, "You haven't picked Image");
                            productImagesList.clear();
                        }
                    } else {
                        productImagesList.clear();
                    }
                } catch (Exception e) {
                    e.printStackTrace();
                    showToast(this, "Something went wrong");
                    productImagesList.clear();
                }
            });
}

getPathFromURI()是下面定义的方法

 public String getPathFromURI(Context context, Uri contentUri) {
    OutputStream out;
    File file = getPath();

    try {
        if (file.createNewFile()) {
            InputStream iStream = context != null ? context.getContentResolver().openInputStream(contentUri) : context.getContentResolver().openInputStream(contentUri);
            byte[] inputData = getBytes(iStream);
            out = new FileOutputStream(file);
            out.write(inputData);
            out.close();
            return file.getAbsolutePath();
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
    return null;
}

private byte[] getBytes(InputStream inputStream) throws IOException {
    ByteArrayOutputStream byteBuffer = new ByteArrayOutputStream();
    int bufferSize = 1024;
    byte[] buffer = new byte[bufferSize];

    int len = 0;
    while ((len = inputStream.read(buffer)) != -1) {
        byteBuffer.write(buffer, 0, len);
    }
    return byteBuffer.toByteArray();
}

getPath( )是

private File getPath() {
    File folder = new File(Environment.getExternalStorageDirectory(), "Download");
    if (!folder.exists()) {
        folder.mkdir();
    }
    return new File(folder.getPath(), System.currentTimeMillis() + ".jpg");
}
于 2021-07-26T09:34:08.153 回答
0

改用这种方法.. 

public String getImagePathFromUri(Uri contentUri) {
            String res = null;
            String[] proj = {MediaStore.Images.Media.DATA};
            Cursor cursor = getContentResolver().query(contentUri, proj, null, null, null);
            if (cursor.moveToFirst()) {
                int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
                res = cursor.getString(column_index);
            }
            cursor.close();
            return res;
        }
于 2020-01-17T07:51:29.960 回答
0

改为使用Document provider。

例如：

Intent it = new Intent();
it.setAction(Intent.ACTION_GET_CONTENT);
it.setType("image/*");
startActivityForResult(it, 1000);

----------------------

@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == 1000) {
        if (resultCode == Activity.RESULT_OK && data != null) {
            try {
                Bitmap bm = getBitmapFromUri(data.getData());
                iv.setImageBitmap(bm);
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }
}

private Bitmap getBitmapFromUri(Uri uri) throws IOException {
    ParcelFileDescriptor parcelFileDescriptor =
            getContentResolver().openFileDescriptor(uri, "r");
    FileDescriptor fileDescriptor = parcelFileDescriptor.getFileDescriptor();
    Bitmap image = BitmapFactory.decodeFileDescriptor(fileDescriptor);
    parcelFileDescriptor.close();
    return image;
}
于 2021-01-15T10:31:47.747 回答