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我有在 3d 空间中旋转的绘图(具有 x 和 y 坐标的点数组): http ://www.motiondraw.com/md/as_samples/Testing/_mindreader/main.html

就像现在一样,这幅画看起来就像包裹在一个立方体上,角落里有一个令人讨厌的 90° 度。相反,它应该看起来好像被包裹在一个圆柱体上。在开始旋转之前,我调用一个函数(在 ActionScript 中)“bendDrawing”,它为每个点设置一个初始 z 值:

for (var j = 0; j < numPoints; j++ ) {
// 绘图居中 – 中心左侧的点 < 0 var distFromCenter = Math.abs(shape[i].points[j].x);

var wid = 350;// this could be the radius of the cylinder

// NOTE: suboptimal, as the image gets a 90° corner in the center, at its highest point
// what it should look like: as if the image was wrapped around a cylinder, i.e. in a circular shape
// is that pythagoras? draw triangle, calc distance from base, add to this to c?
var z = wid - distFromCenter;

shape[i].points[j].z =  Math.abs( z);

}

我只是无法解决这个问题;-) 任何指针都非常感谢!

安德烈亚斯·韦伯

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1 回答 1

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尝试这个:

shape[i].points[j].z  = 
    wid * Math.cos((shape[i].points[j].x / wid) * (0.5 * Math.PI));
于 2011-05-12T04:55:01.133 回答