multithreading - 如何将字符串发送到 _beginthreadex 以供线程读取？

Question

我想使用 _beginthreadex 并传递一个字符串，即域的名称。通过它的正确方法/最佳实践是什么？

1. 通过变量本身（sDomain）？

    WCHAR sDomain[256] = {0};
    //...copy domain into sDomain
    UINT threadID = 0;
    HANDLE hThread = (HANDLE)_beginthreadex(NULL, 0, &Thread_SaveDomainName, sDomain, 0, &threadID);

2. 还是通过变量的地址（&sDomain）？

    WCHAR sDomain[256] = {0};
    //...copy domain into sDomain
    UINT threadID = 0;
    HANDLE hThread = (HANDLE)_beginthreadex(NULL, 0, &Thread_SaveDomainName, &sDomain, 0, &threadID);

3. 还是我制作一个结构并传递结构元素（&sDomain[0]）？

    struct strDomain {TCHAR sDomain[256];};
    strDomain *sDomain = new strDomain[1]();
    //...copy domain into strDomain[0].sDomain
    UINT threadID = 0;
    HANDLE hThread = (HANDLE)_beginthreadex(NULL, 0, &Thread_SaveDomainName, &sDomain[0], 0, &threadID);

Answer 1

下面是最简单的代码实现，当然你可以自定义一些类型来传递，因为线程函数的参数类型是void，你可以做任何转换

#include <iostream>
using namespace std;

UINT Thread_SaveDomainName(LPVOID params)
{
    char* szDomain = (char*)params;
    cout<<szDomain<<endl;
    
    return 0;
}

int main()
{
    char* szDomain = "8080";
    UINT threadID = -1;
    HANDLE hThread = (HANDLE)_beginthreadex(NULL, 0, &Thread_SaveDomainName, (void*)szDomain, 0, &threadID);
    
    return 0;
}