3

我有一个 Spring Boot (kotlin) 项目，我使用 springdoc-openapi 生成 OpenApi 3 规范。我的数据模型如下所示：

open class Animal
data class Cat(val catName: String) : Animal()
data class Dog(val dogName: String) : Animal()

open class Food<T : Animal>
class CatFood : Food<Cat>()
class DogFood : Food<Dog>()

和一个像这样的简单控制器：

@GetMapping("/test")
fun test(): Food<out Animal> = DogFood()

生成的 yaml 是：

openapi: 3.0.1
info:
  title: OpenAPI definition
  version: v0
servers:
- url: http://localhost:8085
paths:
  /test:
    get:
      tags:
      - test-controller
      operationId: test
      responses:
        "200":
          description: default response
          content:
            '*/*':
              schema:
                $ref: '#/components/schemas/FoodAnimal'
components:
  schemas:
    FoodAnimal:
      type: object

这里的问题是我的控制器可以返回DogFoodor CatFood，并且在返回类型中指定。我希望生成的架构是：

openapi: 3.0.1
info:
  title: OpenAPI definition
  version: v0
servers:
- url: http://localhost:8085
paths:
  /test:
    get:
      tags:
      - test-controller
      operationId: test
      responses:
        "200":
          description: default response
          content:
            '*/*':
              schema:
                oneOf:
                  - $ref: '#/components/schemas/FoodAnimal'
                  - $ref: '#/components/schemas/DogFood'
                  - $ref: '#/components/schemas/CatFood'

components:
  schemas:
    FoodAnimal:
      type: object
    CatFood:
      allOf:
        - $ref: '#/components/schemas/FoodAnimal'
      type: object
    DogFood:
      allOf:
        - $ref: '#/components/schemas/FoodAnimal'
      type: object

有没有办法做到这一点？

4

2 回答 2

12

对于继承，您只需要在父类上添加 @Schema 注释：

@Schema(
        type = "object",
        title = "Food",
        subTypes = [CatFood::class, DogFood::class]
)
open class Food<T : Animal>
class CatFood : Food<Cat>()
class DogFood : Food<Dog>()

如果您需要使用 oneOf 进行响应，则必须添加 @Response：

@GetMapping("/test")
@ApiResponse(content = [Content(mediaType = "*/*", schema = Schema(oneOf = [Food::class, CatFood::class,DogFood::class]))])
fun test(): Food<out Animal> = DogFood()
于 2020-01-23T16:11:45.250 回答
2

我在使用带有嵌套属性继承的 OpenApi 时遇到了问题。

我使用 JsonSubtype 注释和泛型作为解决方法。

data class AnimalResponse<FoodResponse>(
    val id: UUID,
    val eats: FoodResponse
)

@JsonSubTypes(value = [
    JsonSubTypes.Type(
        value = CatFoodResponse::class,
        name = "CAT_FOOD"
    ), JsonSubTypes.Type(
        value = DogFoodResponse::class,
        name = "DOG_FOOD"
    )])
interface FoodResponse

这将在 AnimalResponse Schema 中显示所有类型的 FoodResponse。

于 2020-08-10T15:29:35.627 回答