我有以下一段代码。
import java.util.Arrays;
import java.util.Collections;
import java.util.Map;
import java.util.TreeMap;
import java.util.stream.Collectors;
public final class Main {
public static void main(final String[] args) {
final Object[][] pairs = { { "Arka Gdynia", Collections.emptyList() },
{ "Legia Warszawa", Collections.emptyList() }, { "ŁKS Łódź", Collections.emptyList() },
{ "Śląsk Wrocław", Collections.emptyList() }, { "Wisła Kraków", Collections.emptyList() }, };
final Map<String, Object> clubPlayerMap = Arrays.stream(pairs)
.collect(Collectors.toMap(c -> c[0].toString(), c -> c[1], (o1, o2) -> o1, TreeMap::new));
for (final String key : clubPlayerMap.keySet()) {
System.out.println(key);
}
}
}
不幸的是,这不会产生我想要的结果。键需要根据波兰排序规则进行排序。
Arka Gdynia
Legia Warszawa
Wisła Kraków
ŁKS Łódź
Śląsk Wrocław
我期望的结果是
Arka Gdynia
Legia Warszawa
ŁKS Łódź
Śląsk Wrocław
Wisła Kraków
所以我用谷歌搜索并找到了一种方法来做到这一点java.text.Collator
。stream()
但是,我想知道是否可以将其与和一起作为单行来执行collect()
。
我想出的解决方案如下,但不幸的是它不是很整洁。
import java.text.Collator;
import java.util.Arrays;
import java.util.Collections;
import java.util.Locale;
import java.util.Map;
import java.util.TreeMap;
import java.util.stream.Collectors;
public final class Main {
public static void main(final String[] args) {
final Object[][] pairs = { { "Arka Gdynia", Collections.emptyList() },
{ "Legia Warszawa", Collections.emptyList() }, { "ŁKS Łódź", Collections.emptyList() },
{ "Śląsk Wrocław", Collections.emptyList() }, { "Wisła Kraków", Collections.emptyList() }, };
final Map<String, Object> clubPlayerMapCollated = new TreeMap<>(Collator.getInstance(new Locale("pl", "PL")));
final Map<String, Object> clubPlayerMap = Arrays.stream(pairs)
.collect(Collectors.toMap(c -> c[0].toString(), c -> c[1], (o1, o2) -> o1, TreeMap::new));
clubPlayerMapCollated.putAll(clubPlayerMap);
for (final String key : clubPlayerMapCollated.keySet()) {
System.out.println(key);
}
}
}
是否有可能从单线生成地图?