47

I have a textbox in Javascript. When I enter '0000.00' in the textbox, I want to know how to convert that to only having one leading zero, such as '0.00'.

4

8 回答 8

54

更简化的解决方案如下。看一下这个！

var resultString = document.getElementById("theTextBoxInQuestion")
                           .value
                           .replace(/^[0]+/g,"");
于 2009-08-12T09:45:21.993 回答
35 
str.replace(/^0+(?!\.|$)/, '')

  '0000.00' --> '0.00'   
     '0.00' --> '0.00'   
  '00123.0' --> '123.0'   
        '0' --> '0'
于 2012-12-24T20:17:38.657 回答
14 
var value= document.getElementById("theTextBoxInQuestion").value;
var number= parseFloat(value).toFixed(2);
于 2009-02-27T11:15:49.423 回答
9

It sounds like you just want to remove leading zeros unless there's only one left ("0" for an integer or "0.xxx" for a float, where x can be anything).

This should be good for a first cut:

while (s.charAt(0) == '0') {            # Assume we remove all leading zeros
    if (s.length == 1) { break };       # But not final one.
    if (s.charAt(1) == '.') { break };  # Nor one followed by '.'
    s = s.substr(1, s.length-1)
}
于 2009-02-27T11:17:50.760 回答
6

Ok a simple solution. The only problem is when the string is "0000.00" result in plain 0. But beside that I think is a cool solution.

var i = "0000.12";
var integer = i*1; //here's is the trick...
console.log(i); //0000.12
console.log(integer);//0.12

For some cases I think this can work...

于 2013-06-05T16:08:45.967 回答
5

您可以使用以下代码：

<script language="JavaScript" type="text/javascript">
<!--
function trimNumber(s) {
  while (s.substr(0,1) == '0' && s.length>1) { s = s.substr(1,9999); }
  return s;
}

var s1 = '00123';
var s2 = '000assa';
var s3 = 'assa34300';
var s4 = 'ssa';
var s5 = '121212000';

alert(s1 + '=' + trimNumber(s1));
alert(s2 + '=' + trimNumber(s2));
alert(s3 + '=' + trimNumber(s3));
alert(s4 + '=' + trimNumber(s4));
alert(s5 + '=' + trimNumber(s5));
// end hiding contents -->
</script>
于 2011-11-26T05:23:00.673 回答
2

Try this:

<input type="text" onblur="this.value=this.value.replace(/^0+(?=\d\.)/, '')">
于 2009-02-27T11:15:30.937 回答
1

您可以使用正则表达式将前导零替换为一个：

valueString.replace(/^(-)?0+(0\.|\d)/, '$1$2')

>'-000.0050'.replace(/^(-)?0+(0\.|\d)/, '$1$2')
< "-0.0050"
>'-0010050'.replace(/^(-)?0+(0\.|\d)/, '$1$2')
< "-10050"

火柴：<beginning of text><optional minus sign><any sequence of zeroes><either a zero before the dot or another digit>

替换为：<same sign if available><the part of the string after the sequence of zeroes>

  • ^ 是文本的开头

  • ? 表示可选（指前一个字符）

  • (a|b) 表示 a 或 b

  • . 是点（转义为 . 有特殊含义）

  • \d 是任何数字

  • $1 表示你在第一组 () 中找到的

  • $2 表示你在第二组 () 中找到的

于 2018-10-17T13:11:45.283 回答