定义映射的最佳方法是什么: Map(1 -> "One", 2 -> "Two") 并定义一个与上述函数匹配的函数?我正在考虑通过 Javascript 定义字典并在函数体中进行匹配。一个例子会很棒。谢谢
1 回答
1
下面是 BigQuery 标准 SQL 的示例
#standardSQL
CREATE TEMP FUNCTION MAP(expr ANY TYPE, map ANY TYPE, `default` ANY TYPE ) AS (
IFNULL((
SELECT result
FROM (SELECT NULL AS search, NULL AS result UNION ALL SELECT * FROM UNNEST(map))
WHERE search = expr), `default`)
);
WITH `project.dataset.table` AS (
SELECT 1 id, 4 location_id UNION ALL
SELECT 2, 2 UNION ALL
SELECT 3, 5
)
SELECT id, location_id,
MAP(location_id,
[ (1, 'Los Angeles'),
(2, 'San Francisco'),
(3, 'New York'),
(4, 'Seattle')
], 'Non US') AS `Location`
FROM `project.dataset.table`
结果
Row id location_id Location
1 1 4 Seattle
2 2 2 San Francisco
3 3 5 Non US
于 2019-12-18T21:42:35.267 回答