6

正如标题所说，我正在使用 Symfony 5 构建一个 API。我有一些需要不同用户权限的控制器，我想测试它们，所以我决定创建两个具有不同角色的用户用于测试目的 -ROLE_USER和ROLE_ADMIN. 当前代码是这样的（注意，它不是完整的代码，只是一个虚拟示例/起点）

ApiTestCase.php

<?php

namespace App\Tests;

use App\Entity\User;
use App\Tests\Http\RequestBuilder;
use Symfony\Bundle\FrameworkBundle\Test\WebTestCase;

class ApiTestCase extends WebTestCase
{

    private static $userData = [
        'firstName' => 'Pera',
        'lastName'  => 'Peric',
        'email'     => 'test.user@test.com',
        'password'  => 'test123',
        'roles'     => [
            'ROLE_USER'
        ]
    ];

    private static $adminUserData = [
        'firstName' => 'Admin',
        'lastName'  => 'Adminovic',
        'email'     => 'admin.user@test.com',
        'password'  => 'admin123',
        'roles'     => [
            'ROLE_ADMIN'
        ]
    ];

    public static function createTestUser()
    {
        $res = RequestBuilder::create(self::createClient())
            ->setMethod('POST')
            ->setUri('/api/v1/security/register')
            ->setJsonContent(self::$userData)
            ->getResponse();

        $data = $res->getJsonContent();
        return $data['data'];
    }

    public static function createTestAdminUser()
    {
        $res = RequestBuilder::create(self::createClient())
            ->setMethod('POST')
            ->setUri('/api/v1/security/register')
            ->setJsonContent(self::$adminUserData)
            ->getResponse();

        $data = $res->getJsonContent();
        var_dump($data);
        return $data['data'];
    }

    public static function deleteTestUser()
    {
        self::createClient()->getContainer()
            ->get('doctrine.orm.entity_manager')
            ->getRepository(User::class)
            ->deleteUserByEmail(self::$userData['email']);
    }

    public static function deleteTestAdminUser()
    {
        self::createClient()->getContainer()
            ->get('doctrine.orm.entity_manager')
            ->getRepository(User::class)
            ->deleteUserByEmail(self::$adminUserData['email']);
    }

}

LocationControllerTest.php


namespace App\Tests;

use PHPUnit\Framework\TestCase;
use Symfony\Bundle\FrameworkBundle\Test\WebTestCase;

class LocationControllerTest extends ApiTestCase
{
    public static $user;
    public static $adminUser;

    public static function setUpBeforeClass()
    {
        self::$user = self::createTestUser();
        self::$adminUser = self::createTestAdminUser();
    }

    public function testUsersExist()
    {
        // this is jut to test out an idea
        $this->assertContains('ROLE_USER', self::$user['roles']);
        $this->assertContains('ROLE_ADMIN', self::$adminUser['roles']);
    }

    public static function tearDownAfterClass()
    {
        self::deleteTestUser();
        self::deleteTestAdminUser();
    }
}

当我运行测试时（sunit是别名php bin/phpunit）：

➜  skeleton master ✗ (*?) sunit --filter LocationController                                                                                                              [10:12AM]
PHPUnit 7.5.17 by Sebastian Bergmann and contributors.

Testing Project Test Suite
E                                                                   1 / 1 (100%)

Time: 742 ms, Memory: 24.00 MB

There was 1 error:

1) App\Tests\LocationControllerTest::testUsersExist
LogicException: Booting the kernel before calling Symfony\Bundle\FrameworkBundle\Test\WebTestCase::createClient() is not supported, the kernel should only be booted once. in /Users/shkabo/code/skeleton/vendor/symfony/framework-bundle/Test/WebTestCase.php:44
Stack trace:
#0 /Users/shkabo/code/skeleton/tests/ApiTestCase.php(45): Symfony\Bundle\FrameworkBundle\Test\WebTestCase::createClient()
#1 /Users/shkabo/code/skeleton/tests/LocationControllerTest.php(16): App\Tests\ApiTestCase::createTestAdminUser()
#2 /Users/shkabo/code/skeleton/bin/.phpunit/phpunit-7.5-0/src/Framework/TestSuite.php(703): App\Tests\LocationControllerTest::setUpBeforeClass()
#3 /Users/shkabo/code/skeleton/bin/.phpunit/phpunit-7.5-0/src/Framework/TestSuite.php(746): PHPUnit\Framework\TestSuite->run(Object(PHPUnit\Framework\TestResult))
#4 /Users/shkabo/code/skeleton/bin/.phpunit/phpunit-7.5-0/src/TextUI/TestRunner.php(652): PHPUnit\Framework\TestSuite->run(Object(PHPUnit\Framework\TestResult))
#5 /Users/shkabo/code/skeleton/bin/.phpunit/phpunit-7.5-0/src/TextUI/Command.php(206): PHPUnit\TextUI\TestRunner->doRun(Object(PHPUnit\Framework\TestSuite), Array, true)
#6 /Users/shkabo/code/skeleton/bin/.phpunit/phpunit-7.5-0/src/TextUI/Command.php(162): PHPUnit\TextUI\Command->run(Array, true)
#7 /Users/shkabo/code/skeleton/bin/.phpunit/phpunit-7.5-0/phpunit(17): PHPUnit\TextUI\Command::main()
#8 /Users/shkabo/code/skeleton/vendor/symfony/phpunit-bridge/bin/simple-phpunit.php(291): include('/Users/shkabo/c...')
#9 /Users/shkabo/code/skeleton/bin/phpunit(13): require('/Users/shkabo/c...')
#10 {main}
ERRORS!
Tests: 1, Assertions: 0, Errors: 1.

我理解错误，但似乎无法找到解决方案/这种方法。我也很有可能做错了。

在数据库中，第一个用户被创建，而第二个用户在我尝试创建它时抛出此错误。

我想要实现的是我有（静态）方法，我可以调用并创建虚拟用户/位置/等。并将其用于测试该特定控制器，并在完成对该特定控制器的测试后将其从数据库中销毁/删除。

RequestBuilder https://github.com/nebkam/fluent-test/blob/master/src/RequestBuilder.php

4

3 回答 3

7

您可以self::ensureKernelShutdown()根据官方建议在创建客户之前致电。

self::ensureKernelShutdown();
$sally = static::createClient();

我不确定这是否可以解决这个问题，但我遇到了类似的问题，谷歌将我带到了这里。

https://github.com/symfony/symfony-docs/issues/12961

于 2020-09-15T18:02:04.200 回答
5

问题是因为您使用了 2 次static::createClient()，这将再次启动内核。为避免这种情况，您可以创建一个客户端，然后克隆它并使用方法修改一些参数并将客户端作为参考传递。

在这里你可以找到我昨天在 repo 中写的一个问题和我找到的解决方案

private static ?KernelBrowser $client = null;
    protected static ?KernelBrowser $admin = null;
    protected static ?KernelBrowser $user = null;

    /**
     * @throws \Exception
     */
    public function setUp(): void
    {
        $this->resetDatabase();

        if (null === self::$client) {
            self::$client = static::createClient();
        }

        if (null === self::$admin) {
            self::$admin = clone self::$client;
            $this->createAuthenticatedClient(self::$admin, 'admin@api.com', 'password');
        }

        if (null === self::$user) {
            self::$user = clone self::$client;
            $this->createAuthenticatedClient(self::$user, 'user@api.com', 'password');
        }
    }

    protected function createAuthenticatedClient(KernelBrowser &$client, string $username, string $password): void
    {
        $client->request(
            'POST',
            '/api/v1/login_check',
            [
                '_email' => $username,
                '_password' => $password,
            ]
        );

        $data = \json_decode($client->getResponse()->getContent(), true);

        $client->setServerParameter('HTTP_Authorization', \sprintf('Bearer %s', $data['token']));
        $client->setServerParameter('CONTENT_TYPE', 'application/json');
    }

更多细节在https://github.com/symfony/symfony/issues/35031

于 2019-12-19T09:25:53.017 回答
0

Client我有同样的问题，并通过初始化setUp()

protected function setUp(): void
{
    $this->client = $this->makeClient();
    $this->client->followRedirects();
    ...
}

在测试中我$this->client->loginUser()用来登录用户，将身份验证防火墙类型作为第二个参数

public function testWhateverYouNeed(): void
{
    ... // Get the user from fixtures
    $this->client->loginUser($user, 'admin');
}

防火墙定义在config/packages/security.yaml

于 2020-08-24T13:04:50.717 回答