我有目标值数组和组件列表需要选择每个或其中一些的最佳比率,以使最终回报率为 100 % 或更低,并在 java 中以最低成本满足目标数组这是我尝试过的代码解决问题,它可以根据我的需要正常工作,但需要很长时间并且需要一些优化
输入
- InputMaxRates[] -- 最终解决方案可以从第 i 个保护中获得的最大可能速率
- inputMinRates[] -- 最终解决方案可以从第 i 个保护中获得的最小可能速率(如果包含)
- valuesMatrix[][] --第 i 个保护中 100% 内的值的数组
- targetsArray[] -- 最终框需要覆盖的目标值
- costOfTheProdects[] -- 如果第 i 个保护,则为 100% 的成本
- IsRequired[] --boolen 数组来判断第 i 个保护是否必须在最后一个框中
输出
- 具有输入大小的数组保护具有最佳比率的每个/一些满足以最小成本输出的目标的保护的数量必须是总数为 100 或更少的数组,如果没有可能的解决方案,则返回 -1 的数组
任何人都可以帮忙,这是我的代码
import java.util.Arrays;
import java.util.Vector;
import javax.swing.JOptionPane;
import javax.swing.JTable;
public class AISolver {
double InputMaxRates[], inputMinRates[] , costOfTheProdects[];
double targetsArray[];
double[] bestRatios = null;
double[] bestValues = null;
boolean IsRequired[];
double minPriceCost = 1000000000;
int minPriceMet = -1;
double[][] valuesMatrix;
int numberOfTargets = 9;//number of vectors
int numberOfRows = 0;
public AISolver(double[] InputMaxRates, double[] inputMinRates, double[][] valuesMatrix,
double[] targetsArray, boolean IsRequired[], double[] costOfTheProdects) {
this.InputMaxRates = InputMaxRates;
this.inputMinRates = inputMinRates;
this.valuesMatrix = valuesMatrix;
this.targetsArray = targetsArray;
this.costOfTheProdects = costOfTheProdects;
this.IsRequired = IsRequired;
numberOfTargets = targetsArray.length;
numberOfRows = inputMinRates.length;
}
int hitflag = 0;
private void checkTheVictor(Vector<Double> v) {
double[] thisRatioValues = getTheNewValues(v);
double thisRatioCost = calcCostFromRates(v);
int checkmet = checkMeetTargets(thisRatioValues);
if (checkmet > 0 && checkmet >= minPriceMet) {
if (checkmet > minPriceMet) {
//JOptionPane.showMessageDialog(dataTable, "Meet -> " + minPriceMet);
minPriceCost = 1000000000;
}
minPriceMet = checkmet;
if (checkmet == numberOfTargets) {
// JOptionPane.showMessageDialog(dataTable, "Meet -> " + minPriceMet + " cost = " + thisRatioCost);
// if (hitflag == 0) {
// minPriceCost = 1000000000;
// }
if (minPriceCost > thisRatioCost) {
minPriceCost = thisRatioCost;
bestRatios = new double[numberOfRows];
for (int i = 0; i < bestRatios.length; i++) {
try {
bestRatios[i] = v.get(i);
} catch (Exception e) {
bestRatios[i] = 0;
}
}
bestValues = new double[numberOfTargets];
for (int i = 0; i < thisRatioValues.length; i++) {
bestValues[i] = thisRatioValues[i];
}
}
}
}
}
public double[] bestRatioFinder(Vector<Double> v) {
if ((v.size() == numberOfRows && getRatesVectorSum(v) <= 100) || getRatesVectorSum(v) >= 100) {
checkTheVictor(v);
} else if (inputMinRates[v.size()] == InputMaxRates[v.size()]) {
v.add(inputMinRates[v.size()]);
bestRatioFinder(v);
} else {
//leave the prodect option
if (IsRequired[v.size()] == false) {
v.add(0.0);
// new Thread(() -> {
// Vector<Double> vt = new Vector<>();
// for (Double tx : v) {
// vt.add(tx);
// }
// bestRatioFinder(v);
// }).start();
bestRatioFinder(v);
v.removeElementAt(v.size() - 1);
}
//contune
Double maxPossibleRate = Math.min(101 - getRatesVectorSum(v), InputMaxRates[v.size()] + 1);
for (Double i = inputMinRates[v.size()]; i < maxPossibleRate; i++) {
v.add(i);
//System.out.println(Arrays.toString(v.toArray()));
// new Thread(() -> {
// Vector<Double> vt = new Vector<>();
// for (Double tx : v) {
// vt.add(tx);
// }
// bestRatioFinder(v);
// }).start();
bestRatioFinder(v);
v.removeElementAt(v.size() - 1);
}
}
return bestRatios;
}
private int getRatesVectorSum(Vector<Double> v) {
int sum = 0;
for (int i = 0; i < v.size(); i++) {
Double el = v.elementAt(i);
sum += el;
}
return sum;
}
private double calcCostFromRates(Vector<Double> v) {
double sum = 0;
for (int i = 0; i < v.size(); i++) {
Double el = v.elementAt(i);
double cost = costOfTheProdects[i];
sum += el * cost;
}
return sum;
}
private double[] getTheNewValues(Vector<Double> v) {
//need to update
double[] gvalus = new double[numberOfTargets];
for (int rowCounter = 0; rowCounter < v.size(); rowCounter++) {
Double el = v.elementAt(rowCounter);
for (int colCounter = 0; colCounter < numberOfTargets; colCounter++) {
Double cItemRatio = el;
double theCourntValueOfTheItem = valuesMatrix[rowCounter][colCounter];
double theValueToAdd = cItemRatio * theCourntValueOfTheItem / 100;
gvalus[colCounter] += theValueToAdd;
}
}
return gvalus;
}
private int checkMeetTargets(double[] ratvals) {
int met = 0;
for (int i = 0; i < ratvals.length; i++) {
if (ratvals[i] >= targetsArray[i]) {
met++;
}
}
return met;
}
}