python - 使用密码库在 Python 中生成椭圆曲线私钥

Question

我正在尝试使用密码学中的危险材料在 python 中生成一个公共/私有椭圆曲线密钥对。以下是我拥有的当前代码。当我运行时，它正在生成错误“NoneType”对象没有属性“generate_elliptic_curve_private_key”

ecurve = asymmetric.ec.EllipticCurve
ecurve.name = 'secp256r1'
ecurve.key_size = 128
ec_backend = cryptography.hazmat.backends.interfaces.EllipticCurveBackend.generate_elliptic_curve_private_key(cryptography.hazmat.backends.interfaces.EllipticCurveBackend, ecurve)
key = asymmetric.ec.generate_private_key(curve=ecurve, backend=ec_backend)  

这是文档https://cryptography.io/en/latest/hazmat/primitives/asymmetric/ec/#

Answer 1

我看不到generate_elliptic_curve_private_key方法在哪里可用。

以下是生成SECP256R1公钥​​并将其序列化为 PEM 格式的示例：

from cryptography.hazmat.backends import default_backend
from cryptography.hazmat.primitives import serialization
from cryptography.hazmat.primitives.asymmetric import ec

private_key = ec.generate_private_key(ec.SECP256R1(), default_backend())
public_key = private_key.public_key()
# serializing into PEM
rsa_pem = public_key.public_bytes(encoding=serialization.Encoding.PEM, format=serialization.PublicFormat.SubjectPublicKeyInfo)

打印密钥

In [14]: print(rsa_pem.decode())
-----BEGIN PUBLIC KEY-----
MFkwEwYHKoZIzj0CAQYIKoZIzj0DAQcDQgAEilwhueTwySfEbXd9y/inZVsYVG6z
/UJyVbN+cYgtIFd0vLdaP27cME8RGE/enMEcX7/jkb13j2DPnXt2R6teZw==
-----END PUBLIC KEY-----