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每当成功调用以下函数时，Sweetalert 对话框在打开后立即消失，并且位置 reload() 起作用。当 number_of_errors > 0 时，代码完全相同，但在后一种情况下，sweetalert 保持打开状态。当成功为 1 时，我如何使其保持开放状态

注意：由于 ajax 调用，此函数是从另一个 sweetalert 函数调用的。此外，成功/错误图标不显示 :-( 。在 HTML 中很好地引用了 css 和 js 文件

任何想法都将非常受欢迎，请

提前致谢

function show_comment_result(
    success,
    number_of_errors,
    error_messages,
    action
) {
    if (action == "new item") {
        html_success = "The item was successfully added";
        html_errorA =
            '<p>We had an <font color="#ff0000">error</font>: <p>' +
            '<p><font color="#ff0000">' +
            error_messages +
            '</font></p><b><a href="#" id="temp2" onclick="restart_entry(); ">Please Try Again</a></b>';
        html_errorB =
            '<p> <font color="#ff0000">UNKNOWN error occured</font>: <p><b><a href="#" id="temp2" onclick="restart_entry(); ">Please Try Again</a></b>';
    } else if (action == "edit item") {
        html_success = "The item was successfully edited";
        html_errorA =
            '<p>We had an <font color="#ff0000">error</font>: <p>' +
            '<p><font color="#ff0000">' +
            error_messages +
            "</font></p>";
        html_errorB = '<p> <font color="#ff0000">UNKNOWN error occured</font>';
    } else if (action == "delete item") {
        html_success = "The item was successfully deleted";
        html_errorA =
            '<p>We had an <font color="#ff0000">error</font>: <p>' +
            '<p><font color="#ff0000">' +
            error_messages +
            "</font></p>";
        html_errorB = '<p> <font color="#ff0000">UNKNOWN error occured</font>';
    }

    if (success == 1) {
        Swal.fire({
            type: "success",
            title: "Success!",
            icon: "success",
            showConfirmButton: true,
            html: html_success
        });
        if (action == "edit item" || action == "delete item") {
            location.reload();
        } else if (action == "new item") {
            document.getElementById("HiddenForm").reset();
        }
        //$('#HiddenForm')[0].reset();
        if (action == "new item") {
            document.getElementById("HiddenForm").reset();
        }
    } else {
        if (number_of_errors > 0) {
            Swal.fire({
                icon: "error",
                titleText: "Ooops",
                title: "Ooops...",
                showConfirmButton: false,
                html: html_errorA
            });
        } else {
            Swal.fire({
                icon: "error",
                showConfirmButton: false,
                titleText: "Ooops",
                title: "Ooops...",
                html: html_errorB
            });
        }
    }
}
4

1 回答 1

1

你可以这样做：

Swal.fire({
            type: "success",
            title: "Success!",
            icon: "success",
            showConfirmButton: true,
            html: html_success
        }).then(() => {
        if (action == "edit item" || action == "delete item") {
            location.reload();
        } else if (action == "new item") {
            document.getElementById("HiddenForm").reset();
        }
        //$('#HiddenForm')[0].reset();
        if (action == "new item") {
            document.getElementById("HiddenForm").reset();
        }
})
于 2019-11-20T12:11:58.183 回答