zip - How to unzip ServletInputStream using zip4j library

Question

I am uploading a zip file (heap dump) in a request through postman tool and retrieving file content in servlet using request.getInputStream() method.

Postman Image

I have an InputStream that contains zipped bits and would like to decompress that using a ZipInputStream. I did not see any way to currently do this using Zip4j. Currently, the only way to create a ZipInputStream is from a ZipFile which needs to be from a File and not an InputStream. I am looking for something that works similar to the way that java.util.zip.ZipInputStream works.

I have tried java.util.zip.ZipInputStream but getNextEntry() method is returning NULL sometimes. Find my code below,

 ZipInputStream zis = new ZipInputStream(request.getInputStream());
 ZipEntry ze = zis.getNextEntry();
 ByteArrayOutputStream out = new ByteArrayOutputStream();
 byte buffer[] = new byte[1024];

            while(ze!=null) {

                int len;
                while((len = zis.read(buffer)) != -1) {
                    out.write(buffer, 0, len);
                }

                ze = zis.getNextEntry();
            }

            out.close();
            zis.close();

            return out.toByteArray();

Is there any way to achieve this using the zip4j library?

Thanks in advance!