0

我创建了一个模块，模块中的一个类扩展到 ObjectModel ：模块名称：

<?php
if (!defined('_PS_VERSION_'))
    exit;

class StoreOrder extends ObjectModel
{
    public $id_store_order;
    public $id_customer;
    public $nature_piece;
    public $client_code;
    public $internal_reference;
    public $store_code;
    public $store_name;
    public $ticket_date;
    public $custumer_name;
    public $ticket_number;
    public $product_number;
    public $total_ht;
    public $total_ttc;
    public $payment_mode;

    public static $definition = array(
        'table' => 'ps_store_order',
        'primary' => 'id_store_order',
        'fields' => array(
            'id_store_order' => array('type' => self::TYPE_INT),
            'id_customer' => array('type' => self::TYPE_INT),
            'store_code' => array('type' => self::TYPE_STRING),
            'store_name' => array('type' => self::TYPE_STRING),
            'ticket_date' =>    array('type' => self::TYPE_STRING),
            'ticket_number' =>  array('type' => self::TYPE_STRING),
            'product_number' => array('type' => self::TYPE_STRING),
            'total_ht' => array('type' => self::TYPE_STRING),
            'total_ttc' => array('type' => self::TYPE_STRING),
            'payment_mode' => array('type' => self::TYPE_STRING),
        )
    );

    public function __construct()
  {
    parent::__construct();
    }

    public static function getByIdCustomer($id_customer) {
        $sql = "SELECT * FROM `ps_store_order` WHERE `id_customer` = ".$id_customer;
        $result = Db::getInstance()->executeS($sql);
        return $result;
    }


}

但是如果我在其他模块中包含这个类来使用它，它在步骤“_PS_VERSION_”的阻塞没有定义，并且我删除了它什么都不返回的条件（代码是股票我不知道为什么）

谢谢..

4

1 回答 1

0
  • 您不应检查对象模型上的“_PS_VERSION_”
  • 您不应在对象模型上的表名中添加“ps_”前缀：

'table' => 'store_order',

尝试这个：

include_once _PS_MODULE_DIR_ . 'path-to-your-model';
dd(StoreOrder::getByIdCustomer(2));

还建议对 "$id_customer" 使用 (int) ：

$sql = "SELECT * FROM `ps_store_order` WHERE `id_customer` = " . (int)$id_customer;
于 2019-11-13T23:25:21.483 回答