我正在使用以下方法来创建标题中所述的对象:
from dateutil import relativedelta
MA_dict = {'years': 0,
'months': 0,
'weeks': 0,
'days': 1,
'hours': 0,
'minutes': 0,
'seconds': 0}
def dict2relativedelta(dict):
'''
creates relativedelta variable that can be used to calculate dates
'''
dt = relativedelta.relativedelta(years=dict['years'], months=dict['months'], weeks=dict['weeks'], days=dict['days'],
hours=dict['hours'], minutes=dict['minutes'], seconds=dict['seconds'])
return dt
但是,我想简化一下,这样我就可以通过
MA_dict = {'days': 1}
并且该函数将返回相同的值。我怎样才能做到这一点?