3

这听起来很基本，但是：

WORD wSong = 0;
CArchive ar;
...
ar >> wSong;
m_sPublicTalkInfo.iSongStart = static_cast<int>(wSong);

目前，我将其读WORD入特定变量并将其转换。

我可以同时阅读和投射吗？

请注意，我无法序列化int. 它必须是 aWORD并强制转换为int。或者

ar >> wSong;
m_sPublicTalkInfo.iSongStart = static_cast<int>(wSong);
4

2 回答 2

5

我认为没有直接的方法。你可以实现一个辅助函数：

template <typename T, typename U>
T readAndCast (CArchive& ar) {
  U x;
  ar >> x;
  return static_cast<T> (x);
}


m_sPublicTalkInfo.iSongStart = readAndCast<int, WORD>(ar);

在您的程序中使用固定宽度的整数类型可能会更好，也就是说，也许int_least16_t不是int确保类型具有正确的大小。固定WORD为16位，但不是。此外，它是未签名的并且不是，因此在铸造过程中可能会溢出。intWORDint

于 2019-11-07T10:06:49.483 回答
2

如果您希望序列化语法保持一致，这是一个如何创建包装器的示例。它设计用于仅使用积分和 MFC 无符号类型。

#include <iostream>
#include <cstdint>
#include <sstream>
#include <type_traits>

// Fake the MFC types
using BYTE = std::uint8_t;
using WORD = std::uint16_t;
using DWORD = std::uint32_t;
using QWORD = std::uint64_t;

template<typename T>
struct is_valid_save_type : std::bool_constant<
    std::is_same_v<BYTE, T> ||
    std::is_same_v<WORD, T> ||
    std::is_same_v<DWORD, T> ||
    std::is_same_v<QWORD, T>
> {};

template<typename T>
struct is_valid_load_type : is_valid_save_type<T> {};

// Saves type T as a SaveType
template<typename T, typename SaveType>
struct save_as_type
{
    explicit save_as_type(T value) : value(value) {}

    explicit operator SaveType() const
    {
        return static_cast<SaveType>(value);
    }

private:
    T value;

    // This class only works with integrals
    static_assert(std::is_integral_v<T>);

    // SaveType should be BYTE/WORD/DWORD/QWORD only
    static_assert(is_valid_save_type<SaveType>::value);
};

// Loads type T as a LoadType
template<typename T, typename LoadType>
struct load_as_type
{
    explicit load_as_type(T& value) : value_(value) {}

    load_as_type& operator=(LoadType rhs)
    {
        value_ = rhs;
        return *this;
    }

private:
    T& value_;

    // T should be an integral
    static_assert(std::is_integral_v<T>);

    // T must be non-constant
    static_assert(!std::is_const_v<T>);

    // LoadType should be BYTE/WORD/DWORD/QWORD only
    static_assert(is_valid_load_type<LoadType>::value);
};

class CArchive;

// Make the above types serializable
template<typename T, typename SaveType>
CArchive& operator<<(CArchive& ar, save_as_type<T, SaveType> const& s)
{
    ar << static_cast<SaveType>(s);
}

template<typename T, typename LoadType>
CArchive& operator>>(CArchive& ar, load_as_type<T, LoadType> l)
{
    LoadType t{};
    ar >> t;
    l = t;
}

// Use the following two functions in your code
template<typename SaveType, typename T>
save_as_type<T, SaveType> save_as(T const& t)
{
    return save_as_type<T, SaveType>{ t };
}

template<typename LoadType, typename T>
load_as_type<T, LoadType> load_as(T& t)
{
    return load_as_type<T, LoadType>{ t };
}

// Prevent loading into temporaries; i.e. load_as<BYTE>(11);
template<typename T, typename LoadType>
load_as_type<T, LoadType> load_as(const T&& t) = delete;

// Fake MFC Archive
class CArchive
{
public:
    CArchive& operator<<(int i)
    {
        std::cout << "Saving " << i << " as an int\n";
        return *this;
    }

    CArchive& operator<<(BYTE b)
    {
        std::cout << "Saving " << (int)b << " as a BYTE\n";
        return *this;
    }

    CArchive& operator<<(WORD w)
    {
        std::cout << "Saving " << (int)w << " as a WORD\n";
        return *this;
    }

    CArchive& operator<<(DWORD d)
    {
        std::cout << "Saving " << (int)d << " as a DWORD\n";
        return *this;
    }

    CArchive& operator>>(int& i)
    {
        std::cout << "Loading as an int\n";
        return *this;
    }

    CArchive& operator>>(BYTE& b)
    {
        std::cout << "Loading as a BYTE\n";
        return *this;
    }

    CArchive& operator>>(WORD& w)
    {
        std::cout << "Loading as a WORD\n";
        return *this;
    }

    CArchive& operator>>(DWORD& d)
    {
        std::cout << "Loading as a DWORD\n";
        return *this;
    }
};

int main()
{
    CArchive ar;

    int out_1 = 1;
    int out_2 = 2;
    int out_3 = 3;
    int out_4 = 4;

    ar << out_1 <<
        save_as<BYTE>(out_2) <<
        save_as<WORD>(out_3) <<
        save_as<DWORD>(out_4);

    std::cout << "\n";

    int in_1 = 0;
    int in_2 = 0;
    int in_3 = 0;
    int in_4 = 0;

    ar >> in_1 >>
        load_as<BYTE>(in_2) >>
        load_as<WORD>(in_3) >>
        load_as<DWORD>(in_4);

    return 0;
}

输出：

将 1 保存为 int 将
2 保存为 BYTE 将
3 保存为 WORD 将
4 保存为 DWORD

加载为 int
加载为 BYTE
加载为 WORD
加载为 DWORD

于 2019-11-08T00:08:03.797 回答