我正在尝试创建一个端口转发我的 IP 的批处理文件。可以通过命令找到IP ipconfig | findstr IPv4
,但是有多个网卡和多个IP地址。我只想得到一个地址192.168.40.??
192.168.56.1 和 192.168.56.2 是我的 VirtualBox 适配器。我不确定如何在 if 语句中设置条件。
这是 Windows 批处理文件 (*.bat):
ipconfig,findstr:
D:\>ipconfig | findstr IPv4
IPv4 adress . . . . . . . . . : 192.168.56.2
IPv4 adress . . . . . . . . . : 192.168.56.1
IPv4 adress . . . . . . . . . : 192.168.40.19
我尝试了以下批处理文件:
@echo off
setlocal
setlocal enabledelayedexpansion
for /f "usebackq tokens=*" %%a in (`ipconfig ^| findstr IPv4`) do (
for /f delims^=^:^ tokens^=2 %%b in ('echo %%a') do (
for /f "tokens=1-4 delims=." %%c in ("%%b") do (
set _o1=%%c
set _o2=%%d
set _o3=%%e
set _o4=%%f
set _4octet=!_o1:~1!.!_o2!.!_o3!.!_o4!
echo ==start port fowarding==
netsh interface portproxy add v4tov4 listenport=8080 listenaddress=!_4octet! connectport=8080 connectaddress=192.168.56.1
echo ========================
netsh interface portproxy show v4tov4
)
)
)
endlocal
但这在我所有的适配器上运行:
address port address port
--------------- ---------- --------------- ----------
192.168.56.2 8080 192.168.56.1 8080 <- not want
192.168.56.1 8080 192.168.56.1 8080 <- not want
192.168.40.19 8080 192.168.56.1 8080 <- i want only
然后我尝试了:
@echo off
setlocal
setlocal enabledelayedexpansion
for /f "usebackq tokens=*" %%a in (`ipconfig ^| findstr IPv4`) do (
for /f delims^=^:^ tokens^=2 %%b in ('echo %%a') do (
for /f "tokens=1-4 delims=." %%c in ("%%b") do (
set _o1=%%c
set _o2=%%d
set _o3=%%e
set _o4=%%f
set _4octet=!_o1:~1!.!_o2!.!_o3!.!_o4!
echo ==start port fowarding==
if !_4octet!==192.168.56.1
(
)
else if !_4octet!==192.168.56.2
(
)
else
netsh interface portproxy add v4tov4 listenport=8080 listenaddress=!_4octet! connectport=8080 connectaddress=192.168.56.1
echo ========================
netsh interface portproxy show v4tov4
)
)
)
endlocal
但我收到错误:
该命令的语法不正确。
也许原因是变量 (!_4octet!) 工作不正常。
if !_4octet! == 192.168.56.1 (
你能帮我解决这个问题吗?