2

尝试创建一个HashMap由向量​​组成的数据库结构。每个Vec包含Box<dyn Model>.

use std::collections::HashMap;

trait Model {
    fn id(&self) -> i32;
}

struct User;
struct Message;

impl Model for User {
    fn id(&self) -> i32 { 4 }
}

impl Model for Message {
    fn id(&self) -> i32 { 3 }
}

struct DB {
    users: Vec<Box<User>>,
    messages: Vec<Box<Message>>,
    tables: HashMap<String, Vec<Box<dyn Model>>>,
}

impl DB {
    fn new() -> Self {
        let users: Vec<Box<User>> = Vec::new();
        let messages: Vec<Box<Message>> = Vec::new();
        let mut tables: HashMap<String, Vec<Box<dyn Model>>> = HashMap::new();
        tables.insert("users".to_string(), users);
        tables.insert("messages".to_string(), messages);
        Self {
            users,
            messages,
            tables,
        }
    }
}

编译器产生以下错误:

   Compiling playground v0.0.1 (/playground)
error[E0308]: mismatched types
  --> src/lib.rs:37:44
   |
37 |         tables.insert("users".to_string(), users);
   |                                            ^^^^^ expected trait Model, found struct `User`
   |
   = note: expected type `std::vec::Vec<std::boxed::Box<dyn Model>>`
              found type `std::vec::Vec<std::boxed::Box<User>>`

error[E0308]: mismatched types
  --> src/lib.rs:38:47
   |
38 |         tables.insert("messages".to_string(), messages);
   |                                               ^^^^^^^^ expected trait Model, found struct `Message`
   |
   = note: expected type `std::vec::Vec<std::boxed::Box<dyn Model>>`
              found type `std::vec::Vec<std::boxed::Box<Message>>`

为什么编译器不能推断UserMessage实现Model

4

1 回答 1

4

类型Box<dyn Model>Box<User>不可互换。包含一个的集合不能直接转换成另一个,即使是不安全的代码。这些类型是不同的,并且在内存中具有不同的表示形式。它们甚至有不同的尺寸:

println!("{}", std::mem::size_of::<Box<User>>());      // 8
println!("{}", std::mem::size_of::<Box<dyn Model>>()); // 16

Vec<Box<User>>从到转换的唯一方法Vec<Box<dyn Model>>是逐项转换。每个项目都需要像这样强制:

let model: Box<dyn Model> = user;

或者:

let model = Box::<dyn Model>::from(user);

导致了这个丑陋的事情:

tables.insert(
    "users".to_string(),
    users
        .iter()
        .map(|user| Box::<dyn Model>::from(user))
        .collect()
);

如果在此之后不需要原始向量,则可以通过使其可变和耗尽来避免克隆:

tables.insert(
    "users".to_string(),
    users
        .drain(..)
        .map(|user| Box::<dyn Model>::from(user))
        .collect(),
);
于 2019-11-03T19:28:02.873 回答