0

我希望我的 servlet 页面检索 jsp 页面的 textarea 中提供的信息，并将该文本转换为语音并返回到 jsp 页面。这段代码给了我这个错误

org.apache.catalina.core.StandardWrapperValve invokeSEVERE: Servlet.service() for servlet [Myclass] in context with path [/test] throw exception [Servlet execution throw an exception] with root cause java.lang.ClassNotFoundException: com.sun .speech.freetts.VoiceManager在 org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1365)

任何帮助或建议将不胜感激。

servlet 页面 (Myclass.java)

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

        //2nd approach
        final String VOICENAME ="kevin16" ;
        String button = request.getParameter("button");
        Voice voice;

        VoiceManager vm= VoiceManager.getInstance();
        voice =vm.getVoice(VOICENAME);

        voice.allocate();
        if ("text".equals(button)) {

        try {

            voice.speak(request.getParameter("box"));
        }
        catch( Exception e){
            System.out.println(e.getMessage());
        }   
        System.out.println("line 5");
        request.getRequestDispatcher("NewFile.jsp").forward(request, response);

        }

    }

}

jsp 页面 (NewFile.jsp)

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>

 <html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>


<form method="post" action="Myclass" enctype="multipart/form-data">

<textarea name ="box" rows="4" cols="50">

</textarea>
<button value="text" name ="button" type="submit" >Click Me!</button>
</form>
  </body>

</html>
4

0 回答 0