scala - 很高兴从给定的字符串中找到特定的句子？

Question

我想从 Spark 中的字符串中提取特定部分

例如我的字符串是

val b= "URL ftp://216.24.126.75/serversoftware/ocs/OCS_Inventory_NGInstallation_and_Administration_Guide_1.7_EN.odt
MENTION cryptography    201564  http://en.wikipedia.org/wiki/Cryptography
MENTION digital signature   201870  http://en.wikipedia.org/wiki/Digital_signature
TOKEN   decide  153579
TOKEN   Analyze 160938
TOKEN   properly    140437
TOKEN   reselect    78017
TOKEN   writing 60758 "

我想要这样的输出：

(ftp://216.24.126.75/serversoftware/ocs/OCS_Inventory_NGInstallation_and_Administration_Guide_1.7_EN.odt,http://en.wikipedia.org/wiki/Cryptography)
(ftp://216.24.126.75/serversoftware/ocs/OCS_Inventory_NGInstallation_and_Administration_Guide_1.7_EN.odt,http://en.wikipedia.org/wiki/Digital_signature)