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我正在编写一个简单的程序,将员工信息存储到 .txt 文件中。它应该无限地继续写入配置文件,直到选择“n”来关闭文件。问题是每次我输入一个新的Emp。以前的被覆盖了,有人可以帮我看看我的疏忽吗?先感谢您。

#include <iostream>
#include <fstream>
#include <cstdlib>   // needed for exit()  
#include <string>
#include <iomanip>  // needed for formatting

using namespace std;

struct
    {
        string Names;
        string Social;
        double HourlyRate;
        double HoursWorked;
    } employee_info;

int main()
{
    char contn = 'y';
    char exitf = 'n';
  string filename = "employee_info.txt";  // initialize the filename up front
  ofstream outFile;

  outFile.open(filename.c_str());
  fstream file1;
  if (outFile.fail())
  {
    cout << "The file was not successfully opened" << endl;
    exit(1);
  }

  {
      string employee;
    while (contn == 'y')
    {

    cout << "Please enter Employee Name \n";
    getline (cin,employee_info.Names);
    cout << "Please enter Employee Social Security Number \n";
    getline (cin,employee_info.Social);
    cout << "Please enter Employee's Hourly Rate \n";
    cin >> employee_info.HourlyRate;
    cout << "Please enter Hours Worked \n";
    cin >> employee_info.HoursWorked;
    cout << " Enter y if you would like to enter another employee. \nEnter n to write to file. : \n ";

    cin >> contn;
    cin.ignore();

  // set the output file stream formats
  outFile << setiosflags(ios::fixed)
        << setiosflags(ios::showpoint)
        << setprecision(2);

  // send data to the file
  }

  outFile << employee_info.Names <<endl<< employee_info.Social <<endl<< employee_info.HourlyRate <<endl<< employee_info.HoursWorked << endl;
file1.open("employee_info.txt",ios::app);
  }
while (exitf == 'n')
{
  outFile.close();
  cout << "The file " << filename 
       << " has been successfully written." << endl;

  return 0;
}}    
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1 回答 1

1

命名你的结构:

struct employee
{
    string Names;
    string Social;
    double HourlyRate;
    double HoursWorked;
};

然后主要是制作std::vector这些员工结构。

#include <vector>在顶部)然后std::vector<employee> empvec

在 while 循环的顶部,创建一个新的employee employee temp;

在循环结束时,push_back()employee的所有数据。 empvec.push_back(temp);

于 2011-05-02T11:08:24.747 回答