0

我正在使用 RUST 和 Reqwest 从 API 调用以下响应：

壳：

Ok("{\"SETTLEMENTDATE\":\"2019-10-24T12:50:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":68.0464}\n"{\"SETTLEMENTDATE\":\"2019-10-24T12:55:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":67.4408}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:00:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":87.2918}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:05:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":98.1406}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:10:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":87.4789}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:15:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":90.2434}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:20:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":89.8617}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:25:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":97.2639}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:30:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":100.493}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:35:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":93.7984}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:40:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":85.1182}\n
{\"SETTLEMENTDATE\":\"2019-10-24T13:45:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":91.4173}\n\n",
)

我想解析这个输出，并且只在我从调用中收到的第一个数组（下图以粗体显示）中打印“ RRP.DISPATCHPRICE0 ”值：

好的("{\"SETTLEMENTDATE\":\"2019-10-24T12:50:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\": 68.0464 }\n" 。 ..

我对 RUST 仍然很陌生，并试图找出我应该如何最好地实现这一目标。社区中的任何人都可以提供一些建议/帮助。

我尝试了什么：

我一直在使用以下代码：

extern crate serde_json;

use serde_json::Value;

fn main() {
    let data: Value = serde_json::from_str(
//          Ok(
           "{\"SETTLEMENTDATE\":\"2019-10-24T12:50:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":68.0464}\n"
//           {\"SETTLEMENTDATE\":\"2019-10-24T12:55:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":67.4408}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:00:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":87.2918}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:05:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":98.1406}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:10:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":87.4789}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:15:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":90.2434}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:20:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":89.8617}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:25:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":97.2639}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:30:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":100.493}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:35:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":93.7984}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:40:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":85.1182}\n
//            {\"SETTLEMENTDATE\":\"2019-10-24T13:45:00Z\",\"REGIONID\":\"VIC1\",\"RRP.DISPATCHPRICE0\":91.4173}\n\n",
//            )
    )
    .unwrap();



    println!("data: {:?}", data);
    let obj = data.as_object().unwrap();
    let RRP = obj.get("RRP.DISPATCHPRICE0").unwrap();

    println!("Value: {}", RRP);
}

上面打印出我想要的数字并且效果很好，但是当我在“响应”的其余部分发表评论时，我无法让它工作。

请帮忙！:)

4

1 回答 1

0

您的整个字符串不是有效的 JSON，因为它包含多个对象。StreamDeserializer您可以通过使用 a 一个一个地提取对象来绕过它：

for value in Deserializer::from_str (data).into_iter::<Value>() {
    println!("value: {:?}", value.unwrap());
}

操场

于 2019-10-24T06:34:19.797 回答