1

我在使用 openpyxl 创建脚本时遇到问题 - 简而言之，该脚本的目的是读取 excel 表格单元格值并为 Juniper CLI 打印 CLI 命令。

我的问题是我想自动化脚本查找特定行“规则名称”并在之后打印以下列（即源地址/目标地址）的过程

正如您从下面的脚本中看到的那样，我当前的工作是手动输入行号，但如果我可以通过检测特定的约定名称（例如“StackOverflow 1，StackOverflow 2”）并为规则 2 打印另一组命令来自动化它，那就是太棒了，我只是不确定该怎么做。

有没有人可以帮忙。

import openpyxl 
from openpyxl import load_workbook


wb = load_workbook(input('Workbook name: '), data_only=True) 

ws = wb["Sheet name"]

rownumber = int(input('Row Number Of Rule: '))

name = (ws.cell(row=rownumber, column=1).value)
source = (ws.cell(row=rownumber, column=4).value) 
destination = (ws.cell(row=rownumber, column=5).value)
port = (ws.cell(row=rownumber, column=6).value) 
description = (ws.cell(row=rownumber, column=10).value)
fromzone = (ws.cell(row=rownumber, column=2).value)
tozone = (ws.cell(row=rownumber, column=3).value)

print ('set logical-systems security policies from-zone %s to-zone %s policy %s match source-address %s' %(fromzone,tozone,name,source))
print ('set logical-systems security policies from-zone %s to-zone %s policy %s match destination-address %s' %(fromzone,tozone,name,destination))
print ('set logical-systems security policies from-zone %s to-zone %s policy %s match application %s' %(fromzone,tozone,name,port))
print ('set logical-systems security policies from-zone %s to-zone %s policy %s description %s' %(fromzone,tozone,name,description))
print ('set logical-systems security policies from-zone %s to-zone %s policy %s then permit' %(fromzone,tozone,name))
print ('set logical-systems security policies from-zone %s to-zone %s policy %s then log session-init' %(fromzone,tozone,name))
4

0 回答 0