1

我有一个包含 2 个数组的数据对象（团队名称列表）

const data = {
  Liga: ['Alaves','Atletico', 'Barcelona', 'Betis'],
  Premier: ["Arsenal", "Chelsea", "Everton", 'Liverpool']
};

根据我选择的值（Liga 或 Premier），我得到我的球队名单。

这些团队有两个不同的数据得分结果scoresliga和scorespremier

const scoresliga = [
  { day: '0', Alaves: -6, Atletico: -1, Barcelona: -2, Betis: -6},
  { day: '1', Alaves: -7, Atletico: 1, Barcelona: -2, Betis: -6}
];

const scorespremier = [
  { day: '0', Arsenal: -6, Chelsea: -1, Everton: -2, Liverpool: -6},
  { day: '1', Arsenal: -7, Chelsea: 1, Everton: -2, Betis: -6}
];

我的问题是我必须找到一种方法，当我选择“Liga”时，我必须消耗该scoresliga对象，如果我选择“Premier”，我必须消耗scorespremier

这也将解决我在计算目前不是一般功能的团队的平均值时遇到的问题。

这是使用scoresliga数据对象的函数片段，但它需要是 Ligas（Premier 和 Liga）的共享函数。

const getAverage = team => {

  if (isNaN(scoresliga[0][team])) return null;

  return scoresliga.map(x => x[team]).reduce((a, c) => a + c) / scoresliga.length;
};

我已经复制了我的案例，看看这里

4

2 回答 2

1

只需向 getAverage 添加其他属性

const getAverage = (league, team) => {

  if (isNaN(league[0][team])) return null;

  return league.map(x => x[team]).reduce((a, c) => a + c) / 
     league.length;
};

编辑 Recharts 示例

还要在分数中创建一些映射

const scores = {
  Liga: [
    { day: "0", Alaves: -6, Atletico: -1, Barcelona: -2, Betis: -6 },
    { day: "1", Alaves: -7, Atletico: 1, Barcelona: -2, Betis: -6 }
  ],
  Premier: [
    { day: "0", Arsenal: -6, Chelsea: -1, Everton: -2, Liverpool: -6 },
    { day: "1", Arsenal: -7, Chelsea: 1, Everton: -2, Betis: -6 }
  ]
};

在 Chart.js 中

<span>{getAverage(scores[this.state.selectedLeague], this.state.selectedTeam)}</span>

还有，更新

handleLeagueChange = event => {
    const selectedLeague = event.target.value;
    this.setState({ selectedLeague: selectedLeague }, () => {
      this.setState({ selectedTeam: data[selectedLeague][0] });
    });
  };
于 2019-10-22T10:49:19.257 回答
1

championShip我建议你在数组中添加一个键：

const scoresliga = [
  { day: '0', championShip: 'Liga', Alaves: -6, Atletico: -1, Barcelona: -2, Betis: -6},
  { day: '1', championShip: 'Liga', Alaves: -7, Atletico: 1, Barcelona: -2, Betis: -6, championShip: 'Liga'}
];

const scorespremier = [
  { day: '0', championShip: 'Premier',  Arsenal: -6, Chelsea: -1, Everton: -2, Liverpool: -6},
  { day: '1', championShip: 'Premier', Arsenal: -7, Chelsea: 1, Everton: -2, Betis: -6},
  { day: '1', championShip: 'Premier', Chelsea: 1, Everton: -2, Betis: -6}
];

然后你的数组会更容易操作，你可以有一个数组：

let merged = scoresliga.concat(scorespremier);

let desiredTeam = 'Arsenal';
const filteredByTeam = merged.filter(f=> f.championShip === 'Premier' && f[desiredTeam]);
const averageByTeamQuantity = filteredByTeam.reduce((a,c) =>{
  a += +c[desiredTeam];
  return a;
}, 0)/ filteredByTeam.length;


console.log(averageByTeamQuantity);
于 2019-10-22T11:11:37.203 回答