在Mockito-Scala中,您可以像这样存根方法:
myMock.doIt(*) returns 1
myMock.doIt(*,*) returns 1
myMock.doIt(*,*)(*) returns 1
有没有办法一次模拟所有重载的方法?
在Mockito-Scala中,您可以像这样存根方法:
myMock.doIt(*) returns 1
myMock.doIt(*,*) returns 1
myMock.doIt(*,*)(*) returns 1
有没有办法一次模拟所有重载的方法?
ScalaAnswer[T]
可以用来像这样配置模拟的答案
object AnswerAllFoo extends ScalaAnswer[Any] {
def answer(invocation: InvocationOnMock): Any = {
if (invocation.getMethod.getName == "foo") 42 else ReturnsDefaults.answer(invocation)
}
}
然后像这样在模拟创建中传递它
mock[Qux](AnswerAllFoo)
这是一个完整的工作示例
import org.mockito.invocation.InvocationOnMock
import org.mockito.stubbing.{ReturnsDefaults, ScalaAnswer}
import org.scalatest.{FlatSpec, Matchers}
import org.mockito.{ArgumentMatchersSugar, IdiomaticMockito}
trait Qux {
def foo(s: Seq[Int]): Int
def foo(i: Int, j: String): Int
def bar(s: String): String
}
object AnswerAllFoo extends ScalaAnswer[Any] {
def answer(invocation: InvocationOnMock): Any = {
if (invocation.getMethod.getName == "foo") 42 else ReturnsDefaults.answer(invocation)
}
}
class MockAnyOverload extends FlatSpec with Matchers with IdiomaticMockito with ArgumentMatchersSugar {
"Answer[T]" should "should answer all overloaded methods foo" in {
val qux = mock[Qux](AnswerAllFoo)
qux.foo((Seq(1,0))) shouldBe (42)
qux.foo(1, "zar") shouldBe (42)
qux.bar(*) returns "corge"
qux.bar("") shouldBe ("corge")
}
}