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我正在开发一个应用程序客户端以连接 Open Library API ( https://openlibrary.org/developers/api ) 以通过 Gson 从 Google 返回读取的 Json 获取一些信息，但我有一个参数/更改名称的属性。我发送了这个请求https://openlibrary.org/api/books?bibkeys=ISBN:9788580415544&jscmd=details&format=json 通过 ISBN (9788580415544) 搜索并且 json 返回具有这个数字的属性 (ISBN:9788580415544) 我可以' t把里面的信息。如果我使用另一个 ISBN 更改 de 请求，我将得到一个带有另一个参数/属性名称的 json

请问，我该怎么做？

部分退货文件

{
   "ISBN:9788580415544": {
      "info_url": "https://openlibrary.org/books/OL26851485M/O_Guia_Definitivo_do_Mochileiro_das_Galáxias_(Em_Portuguese_do_Brasil)",
      "bib_key": "ISBN:9788580415544",
      "preview_url": "https://openlibrary.org/books/OL26851485M/O_Guia_Definitivo_do_Mochileiro_das_Galáxias_(Em_Portuguese_do_Brasil)",
      "thumbnail_url": "https://covers.openlibrary.org/b/id/8540059-S.jpg",
      "details": {
         "publishers": [
            "Arqueiro"
         ],
         "classifications": {},
         "key": "/books/OL26851485M",
         "source_records": [
            "amazon:8580415543"
         ],
         "title": "O Guia Definitivo do Mochileiro das Galáxias (Em Portuguese do Brasil)",
         "identifiers": {},
         "covers": [
            8540059
         ]
      }
   }
}

模型类

public class Objeto {

    private ObjetoDetalhe obejtodetalhe;

    public ObjetoDetalhe getObejtodetalhe() {
        return obejtodetalhe;
    }

    public void setObejtodetalhe(ObjetoDetalhe obejtodetalhe) {
        this.obejtodetalhe = obejtodetalhe;
    }

    public class ObjetoDetalhe {
        private String info_url;
        private String bib_key;
        private String preview_url;
        private String thumbnail_url;

        public String getInfo_url() {
            return info_url;
        }

        public void setInfo_url(String info_url) {
            this.info_url = info_url;
        }

        public String getBib_key() {
            return bib_key;
        }

        public void setBib_key(String bib_key) {
            this.bib_key = bib_key;
        }

        public String getPreview_url() {
            return preview_url;
        }

        public void setPreview_url(String preview_url) {
            this.preview_url = preview_url;
        }

        public String getThumbnail_url() {
            return thumbnail_url;
        }

        public void setThumbnail_url(String thumbnail_url) {
            this.thumbnail_url = thumbnail_url;
        }

    }

部分代码

{
Gson gson = new Gson();
Objeto obj = new Objeto();
obj = gson.fromJson(jsonBook.toString(), Objeto.class);

System.out.println(obj.getObejtodetalhe().getInfo_url());
System.out.println(obj.getObejtodetalhe().getThumbnail_url());
}
4

2 回答 2

2

我建议将顶级对象作为Map<String, ObjetoDetalhe>

{
   "ISBN:9788580415544": {...}
}

"ISBN:9788580415544"将是关键，而{...}将是ObjetoDetalhe对象。

于 2019-10-20T03:02:05.543 回答
1 
public class Objeto {

    private map<String, ObjetoDetalhe> obejtodetalhe;

    ....

请更换型号

于 2019-10-20T03:15:02.590 回答