unwrap - 无法强制 swift 5 的非可选类型“可达性”的展开值

Question

我在线收到 iOS 13 (swift 5) 的警告 xcode Cannot force unwrap value of non-optional type 'Reachability'11.1let reachability = Reachability()!

我试过了，如果语句和尝试做，但似乎没有一个工作。删除！给出警告“调用可以抛出，但不能从属性初始化器中抛出错误”

import Reachability

class ReachabilityDetect {

   let reachability = Reachability()!

   var dm = DataModel()

   func addObservers(datamodel: DataModel) {
       self.dm = datamodel
       NotificationCenter.default.addObserver(self, selector: #selector(reachabilityChanged(note:)), name: .reachabilityChanged, object: reachability)
       do{
           try reachability.startNotifier()
       }catch{
           Util.DLog("Reachability notifier niet te starten.")
       }
   }

   @objc func reachabilityChanged(note: Notification) {

      let reachability = note.object as! Reachability

       switch reachability.connection {
       case .wifi:
           Util.DLog("WiFi is actief")
           self.dm.dataConnectionisWifi     = true
           self.dm.dataConnectionisCellular = false
       case .cellular:
           Util.DLog("Celluar data is actief")
           self.dm.dataConnectionisWifi     = false
           self.dm.dataConnectionisCellular = true
       case .none:
           Util.DLog("geen celluar of wifi data actief")
           self.dm.dataConnectionisWifi     = false
           self.dm.dataConnectionisCellular = false
       default: break
       }
   }

}

Answer 1

我有同样的问题。

代替

let reachability = Reachability()!

用这个

let reachability = try! Reachability()