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我需要在 Inventor 中添加工程图草图并对其进行编辑。但是，如果已经在编辑另一个草图，我的程序将终止，甚至 try/catch 也无济于事。我找不到显示是否正在编辑的草图的属性。我的主要代码部分在这里：

// All of these three functions pass try/catch perfectly. Program never terminates
Inventor::Application^ App = (Inventor::Application^)Marshal::GetActiveObject("Inventor.Application");
DrawingDocument^ Doc = (DrawingDocument^)App->ActiveDocument;
Sheet^ Sh = Doc->ActiveSheet;

DrawingSketch^ Sk;

try
{
    Sh->Sketches->Add();
    Sk = Sh->Sketches[Sh->Sketches->Count];
    Sk->Edit(); // Crushes the program completely if another sketch is being edited
}
catch (...)
{
    return;
}

我试图循环浏览所有草图并将它们全部关闭。这以一种我无法理解的方式表现。

try
{
    // Note: in Inventor indexes definitely start from 1
    for (int i = 1; i <= Sh->Sketches->Count; i++)
    {
        Sk = Sh->Sketches[i];
        Sk->ExitEdit();
    }
}
catch (...)
{
    return;
}

例如，当草图 2 打开时，尝试关闭草图 1 的第一个循环 (i = 1) 以某种方式关闭了草图 2。而现在无法关闭草图 2 的第二次迭代 (i = 2)，如它已经关闭，调用“catch”并进一步“return”。

4

1 回答 1

1

我不熟悉 C++，但这里是 VBA 示例如何检测绘图草图是否处于编辑模式

Dim oDrawing As DrawingDocument
Set oDrawing = ThisApplication.ActiveDocument

Dim oSheet As Sheet
Set oSheet = oDrawing.ActiveSheet

Dim editedObject As Variant
Set editedObject = ThisApplication.ActiveEditObject

If editedObject.Type = ObjectTypeEnum.kDrawingSketchObject Then
    Dim activeEditSketch As DrawingSketch
    Set activeEditSketch = editedObject
    activeEditSketch.ExitEdit
End If

Dim oSketch As DrawingSketch
Set oSketch = oSheet.Sketches.Add()

我希望，您可以将此代码转换为 C++

于 2019-10-17T19:33:35.927 回答